Answer:
Allocation rate Machining= $50 per machine hour
Explanation:
Giving the following information:
Estimated Machining cost= $4,000,000
Estimated Number of machine hours= 80,000
<u>To calculate the allocation rate for the Machining department, we need to use the following formula:</u>
Allocation rate Machining= total estimated costs for the period/ total amount of allocation base
Allocation rate Machining= 4,000,000 / 80,000
Allocation rate Machining= $50 per machine hour
2, 3, and 4, make the most sense to me. I'm not completely sure about 4, but I'm confident about the other two :)
Answer:
$3,000 and $9,000
Explanation:
In the income statement only four months revenue is recorded i.e from September 1 to December 31
= $9,000 × 4 months ÷ 12 months
= $3,000
And, under the operating activities the whole amount i.e $9,000 is to be recorded and added to the net income as it is inflow of cash and the same is added using the direct method of the cash flow statements
Answer:
Do = $2.00
D1= Do(1+g)1 = $2(1+0.1)1 = $2.20
D2= Do(1+g)2 = $2(1+0.1)2 = $2.42
PHASE 1
V1 = D1/1+ke + D2/(1+ke)2
V1 = 2.20/(1+0.11) + 2.42/(1+0.11)2
V1 = $1.9820 + $1.9641
V1 = $3.9461
PHASE 2
V2 = DN(1+g)/ (Ke-g )(1+k e)n V2 = $2.42(1+0.03)/(0.11-0.03)(1+0.11)2
V2 = $2.4926/$0.0649
V2 = $38.4068
The current stock price is calculated as follows:
Po = V1 + V2
Po = $3.9461 + $38.4068
Po = $42.35
Explanation: This question relates to valuation of shares with 2-phase growth model. The value of shares in the first phase will be determined by discounting the dividend for the 2 years by cost of equity. The dividends for year 1 and year 2 were obtained by subjecting the current dividend paid (Do) to growth rate.
Moreso, the value of shares for the second phase was calculated by considering the last dividend paid(D2) and then subject it to the new growth rate. The adjusted dividend was then capitalized at the appropriate discount rate of the company.
Answer:
the average of two middle numbers
Explanation:
the median is the number in the middle of an arranged from smallest to largest number of a set of numbers
when you have an even number of data there is no 1 number in the middle so you take the average of the 2 middle numbers
