Answer:
0.0244 (2.44%)
Step-by-step explanation:
defining the event T= the chips passes the tests , then
P(T)= probability that the chip is not defective * probability that it passes the test given that is not defective + probability that the chip is defective * probability that it passes the test given that is defective = 0.80 * 1 + 0.20 * 0.10 = 0.82
for conditional probability we can use the theorem of Bayes. If we define the event D=the chip was defective , then
P(D/T)=P(D∩T)/P(T) = 0.20 * 0.10/0.82= 0.0244 (2.44%)
where
P(D∩T)=probability that the chip is defective and passes the test
P(D/T)=probability that the chip is defective given that it passes the test
Answer:
it just be positive 5
Step-by-step explanation:
Answer:
always 1
Step-by-step explanation:
Answer:
<em><u>Olá</u></em><em><u>,</u></em><em><u> </u></em><em><u>tudo</u></em><em><u> </u></em><em><u>bem</u></em><em><u>?</u></em><em><u> </u></em>
<em><u>Me</u></em><em><u> </u></em><em><u>chamo</u></em><em><u> </u></em><em><u>Ana</u></em><em><u> </u></em><em><u>Kesia</u></em><em><u>,</u></em><em><u> </u></em><em><u>muito</u></em><em><u> </u></em><em><u>prazer</u></em><em><u>.</u></em>
<em><u>Nn</u></em><em><u> </u></em><em><u>entendi</u></em><em><u> </u></em><em><u>sua</u></em><em><u> </u></em><em><u>pergunta</u></em><em><u>!</u></em><em><u> </u></em>
<em><u>Mais</u></em><em><u>,</u></em><em><u> </u></em><em><u>mesmo</u></em><em><u> </u></em><em><u>assim</u></em><em><u> </u></em><em><u>obrigada</u></em><em><u> </u></em><em><u>pelos</u></em><em><u> </u></em><em><u>pontos</u></em><em><u>.</u></em>
1) -149, -1; -148, -2; -147, -3
2) No, according to the commutative property of addition, it does not matter the order they are put in.
Hope this helps!
