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lyudmila [28]
3 years ago
10

Write the verbal sentence as an equation. Fourteen minus the product of 3 and a number is 26.

Mathematics
1 answer:
Firdavs [7]3 years ago
8 0

Answer:

14-3x=26

Step-by-step explanation:

When it says "is" and then a number, that means that it is the answer. In this case, 26.

Product means multiplying.

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What are the pattern conbination between these number 18 48 88 128 178 38 68
valentina_108 [34]
18+30=48
48+40=88
88+40=128
128+50=178

Thats all i found so far in the pattern
30,40,40,50
then it drops
by 140 then adds by 30..

I dont know how else to explain it
7 0
3 years ago
Please huryy!!
ArbitrLikvidat [17]

Answer:

1.5

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Find the diagonal of a rectangular frame which measures 77 in. by 36 in.
quester [9]

Answer:

Diagonal of a rectangular frame = 85 inch

Step-by-step explanation:

Given:

Length of rectangle = 77 inch

Width of rectangle = 36 inch

Find:

Diagonal of a rectangular frame

Computation:

Diagonal of a rectangle = √l² + b²

Diagonal of a rectangular frame = √77² + 36²

Diagonal of a rectangular frame = √5,929 + 1,296

Diagonal of a rectangular frame = √7,225

Diagonal of a rectangular frame = 85 inch

7 0
3 years ago
A lottery game has balls numbered 1 through 21. What is the probability of selecting an even numbered ball or an 8? Round to nea
Viktor [21]

Answer: 0.476

Step-by-step explanation:

Let A = Event of choosing an even number ball.

B = Event of choosing an 8 .

Given, A lottery game has balls numbered 1 through 21.

Sample space: S= {1,2,3,4,5,6,7,8,...., 21}

n(S) = 21

Then, A= {2,4,6,8, 10,...(20)}

i.e. n(A)= 10

B= {8}

n(B) = 1

A∪B = {2,4,6,8, 10,...(20)} = A

n(A∪B)=10

Now, the probability of selecting an even numbered ball or an 8 is

P(A\cup B)=\dfrac{n(A\cup B)}{n(S)}

=\dfrac{10}{21}\approx0.476

Hence, the required probability =0.476

7 0
3 years ago
A can in the shape of a right cylinder is filled with 10W-40 oil. The weight of 10W-40 oil is 0.857 gram per cubic centimeter. I
Leya [2.2K]
To solve this, we have to find the volume of the cylinder first.  The formula to be used is V =  \pi  r^{2} h

Given:V= ?r= 6cmh= 10cm
Solution:V =  \pi  r^{2} h
V= (3.14)(6cm)^{2} x 10cmV= (3.14)(36cm^{2}) x 10cmV= (113.04cm^{2}) x 10cmV= 1130.4cm^3
Finding the volume of the cylinder, we can now solve what the weight of the oil is.  Using the formula of density, Density = mass/volume, we can derive a formula to get the weight.
Given:Density = 0.857 gm/cm^3Volume = 1130.4 cm^3
Solution:weight = density x volumew= (0.857 gm/cm^3) (1130.4cm^3)w= 968.7528 gm
The weight of the oil is 968.75 gm.
5 0
3 years ago
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