Question

What is the distance between the points (2,1) and (14,6) on a coordinate plane?

Answer 1

Answer:

The distance between the points (2,1) and (14,6) on a coordinate plane is 13 units.

Step-by-step explanation:

The distance between two points is

$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

It is given that the coordinates of two points are (2,1) and (14,6).

Using distance formula, the distance between two points is

$D=\sqrt{(14-2)^2+(6-1)^2}$

On simplification we get,

$D=\sqrt{(12)^2+(5)^2}$

$D=\sqrt{144+25}$

$D=\sqrt{169}$

$D=13$

Therefore the distance between the points (2,1) and (14,6) on a coordinate plane is 13 units.

Answer 2

The distance between the points will be 13