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Paladinen [302]

3 years ago

7

Daniela is 23 years older than her daughter. in 5 years, their ages will total 63. how old are they now?

1 answer:

pshichka [43]3 years ago

6 0

Both their ages totaled in 5 (years) - 5 (years)

63 - 5 = 58

Current ages totaled = 58 (years)

Daniela is 23 years older than her daughter (as given above) so...

Current ages totaled (58 years) - How many years Daniela is older than her daughter ( 23 years )

58 - 23 = 35

So, Daniela’s age is currently 35 years and her daughter’s age would be 23 years.

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CAN SOMEONE PLEASE HELP ME WITH THIS FUNCTION PROBLEM

ycow [4]

Answer:

Choose f(x) = 11x + 1

Step-by-step explanation:

Note that we will simply plug the value of 2 into the equation for February:

f(2) = 11(2) + 1 = 23

And plug the value of 6 into the equation for June:

f(6) = 11(6) + 1 = 67

Note how the points on the graph seem to match up with these values. If we evaluate following the same style for each:

f(3) = 11(3) + 1 = 34

f(4) = 11(4) + 1 = 45

f(5) = 11(5) + 1 = 56

Note, these values seems to be very close in approximation to the graph points for each month.

The other three functions return values that are just to far away from what are represented in the graph.

Cheers.

8 0

3 years ago

An ice cream store uses 1/5 of a box of ice cream cones everyday. If they have 8 boxes, how many days will they last? Write the

Ad libitum [116K]

Answer:

1.6 days (1 3/5 for simplified form).

Step-by-step explanation:

<u>Given equation:</u>

1/5 * 8

<u>We know that a box survives 1/5 a day.</u>

1/5 * 8 = 1 3/5

<u>It will survive 1 3/5 a day in 8 boxes.</u>

3 0

2 years ago

Apply the power of a power property to simplify the expression (y^4/3 X y^2/3)^-1/2 = (^2)^-1/2

GarryVolchara [31]

Answer: y= root 2, - root 2

Decimal form y= 1.41421356..., -1.41421356...

6 1

2 years ago

Read 2 more answers

F(x) = (x – 3)(x - 2)?

OlgaM077 [116]

Step-by-step explanation:

8 0

2 years ago

Can u help solve these questions please

Tasya [4]

Answer:

Step-by-step explanation:

$\sqrt[4]{(16a^4)^5}=(16a^4)^{\frac{5}{4}}$ [Since, $\sqrt[n]{x}=x^{\frac{1}{n}}$ ]

$=(16)^{\frac{5}{4}}(a^4)^{\frac{5}{4}}$

$=(2^4)^{\frac{5}{4}}(a^4)^{\frac{5}{4} }$

$=(2^{4\times \frac{5}{4}})(a^{4\times \frac{5}{4}})$

$=2^5a^5$

$\sqrt[5]{(b^{\frac{1}{4}})^6}=\sqrt[5]{b^{\frac{6}{4}}}$

$=\sqrt[5]{b^{\frac{3}{2}}}$

$=(b^{\frac{3}{2}})^{\frac{1}{5} }$

$=b^{\frac{3}{10}}$

$\sqrt[3]{\frac{c^{15}}{c^9}}=\sqrt[3]{c^{15-9}}$

$=(c^6)^{\frac{1}{3}}$

$=c^{6\times \frac{1}{3} }$

= c²

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$=\sqrt[4]{2^{(4+4)}d}$

$=\sqrt[4]{(2^8)d}$

$=2^{\frac{8}{4}}d^{\frac{1}{4}}$

$=2^2d^{\frac{1}{4}}$

$=4d^{\frac{1}{4}}$

8 0

3 years ago