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3 years ago

Roberto evaluated 34 ÷ 45 and got an answer of 1516. Which statement is true about his answer?

Mathematics

2 answers:

Bezzdna [24]3 years ago

4 0

Answer:

Roberto is correct because 15/16 x 4/5 = 3/4.

Roberto's solution to the division problem is correct, but

there are no true statements on your list of choices.

Galina-37 [17]3 years ago

3 0

Answer:

Roberto is correct because 15/16 x 4/5 = 3/4.

Step-by-step explanation:

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HELP QUICK!!!<br> THANKS

Misha Larkins [42]

Answer: The answer should be B mate:)

3 0

3 years ago

Use the law of cosines to solve the problem.on a baseball field, the pitcher's mound is 60.5 feet from home plate. during practi

34kurt

Answer: 169.26 feet.

Step-by-step explanation:

Here, The distance of pitcher's mound from the home plate = 60.5 feet

And, the distance covered by ball when it was hit by the bat = 216 feet

Let the outfielder throw the ball from the distance x feet.

Thus, by the below diagram,

$x^2=216^2+60.5^2-2\times 216\times 60.5\times cos(34^{\circ})$

$x^2=46656+3660.25-21667.7259963 =28648.5240037$

$\implies x = 169.258748677\approx 169.26\text{ feet}$

Hence, the outfielder throw the ball from the distance of 169.26 feet Approximately.

7 0

3 years ago

The height of a triangular flower garden is 6 feet more than the length of the base. If the area of the garden is 8 square feet,

Neko [114]

From the text you can derive the following equations:

(1) A = bh/2 = 8
(2) and h = b+6

Fill in h in (1):

b(b+6)/2 = 8 => b^2 + 6b = 16 with the quadratic formula or simply trying some values for b you can find b=2, so h=8.

5 0

4 years ago

Read 2 more answers

A bike rider is traveling at a speed of 15 feet per second. Write an expression for the distance the rider has traveled after s

bija089 [108]

distance = speed x time

distance time

45 ft 3.0 s

87 ft 5.8 s

166.5 ft 11.1 s

210 ft 14.0 s

4 0

3 years ago

Using the pattern, give the coefficients of (x + y)^5 and (x + y)^6

musickatia [10]

Answer:

$(x+y)^5=x^5+5x^4y+10x^3y^2+10x^2y^3+5xy^4+y^5$

$(x+y)^6=x^6+6x^5y+15x^4y^2+20x^3y^3+15x^2y^4+6xy^5+y^6$

Step-by-step explanation:

In order to find the values of $(x+y)^5$ and $(x+y)^6$ , you need to apply the binomial theorem (high-level math you most likely don't need to worry about, it's easier than multiplying all the binomials together).

$(x+y)^5$ = $\sum _{i=0}^5\binom{5}{i}x^{\left(5-i\right)}y^i$ = $\frac{5!}{0!\left(5-0\right)!}x^5y^0+\frac{5!}{1!\left(5-1\right)!}x^4y^1+\frac{5!}{2!\left(5-2\right)!}x^3y^2+\frac{5!}{3!\left(5-3\right)!}x^2y^3+\frac{5!}{4!\left(5-4\right)!}x^1y^4+\frac{5!}{5!\left(5-5\right)!}x^0y^5$ = $x^5+5x^4y+10x^3y^2+10x^2y^3+5xy^4+y^5$ .

$(x+y)^6$ = $\sum _{i=0}^6\binom{6}{i}x^{\left(6-i\right)}y^i$ = $\frac{6!}{0!\left(6-0\right)!}x^6y^0+\frac{6!}{1!\left(6-1\right)!}x^5y^1+\frac{6!}{2!\left(6-2\right)!}x^4y^2+\frac{6!}{3!\left(6-3\right)!}x^3y^3+\frac{6!}{4!\left(6-4\right)!}x^2y^4+\frac{6!}{5!\left(6-5\right)!}x^1y^5+\frac{6!}{6!\left(6-6\right)!}x^0y^6$ = $x^6+6x^5y+15x^4y^2+20x^3y^3+15x^2y^4+6xy^5+y^6$ .

5 0

3 years ago