4/3 of the area of the larger hexagon to the area of the smaller hexagon
Let the sides of the interior hexagon be 2 cm long, then this hexagon is made up of 6 equilateral triangles of side = 2.
The area of this hexagon = 6 * 1 * sqrt3 = 6 sqrt3 ( as the triangle is made up of 2 60-30-90 triangles)
The exterior hexagon is made up of 6 equilateral triangles with altitude 2 and the area = 6 * 2 * (2 / sqrt3 ) = 24 / sqrt3
area exterior hex / interior hex = 24 / sqrt3 * 1 / 6sqrt3 = 24/18
= 4/3
Required ratio = 4/3 answer
Learn more about Equations:
brainly.com/question/16450098
#SPJ4
Answer:
-29
Step-by-step explanation:
C is the answer.
in the original function, when x=0, y=-1
in the new function, to make y=-1, x+3=0, x=-3. From the original 0 to -3 is a shift of 3 units to the left.
Answer:
(2g^2h^3)^(2g^2h^3) OR 4gg^4hh^9
Step-by-step explanation:
