Try this option:
rule: logₐ(bc)=logₐb+logₐc;
according to the rule: log₂(4x)=log₂4+log₂x
answer: log₂4+log₂x
4/5
2(5x+4)=
distribute the 2
10x+8=
subtract 8 from both sides
10x=8
divide 10 from both sides
x=8/10
simplify by 2
x= 4/5
If every single student met one an another, then you would hear 90 hi's. Since there are 45 different combinations of 2 students meeting another, and since there are 2 hi's each meeting, there would be 90.
I hope that this helps.
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