Answer:
36,000 possible codes.
Step-by-step explanation:
I guess you want the total number of arrangements possible.
The first digit can be any number from 0 to 8. the middle numbers must each be any number from 0 to 9 and the last digit must be 2,4,6 or 8.
So the number of arrangements possible = 9 * 10 * 10 * 10 * 4
= 36,000.
<u>Solution</u><u> </u><u>1</u><u> </u><u>:</u><u>-</u>
>> -3 (3 - x) = 2x + 5
>> -3 × (3 - x) = 2x + 5
>> -9 + 3x = 2x + 5
>> 3x - 2x = 9 + 5
>> x = 14
<u>Solution</u><u> </u><u>2</u><u> </u><u>:</u><u>-</u>
>> -6 - 9p = 3p
>> -9p - 3p = 6
>> -12p = 6
>> p = -1/2
<u>Solution</u><u> </u><u>3</u><u> </u><u>:</u><u>-</u>
>> -5 (-4 - a) = 3a + 8
>> -5 × (-4 - a) = 3a + 8
>> 20 + 5a = 3a + 8
>> 5a - 3a = 8 - 20
>> 2a = -12
>> a = -12 / 2
>> a = -6
<u>Solution</u><u> </u><u>4</u><u> </u><u>:</u><u>-</u>
>> s - 6 = -5s
>> s + 5s = 6
>> 6s = 6
>> s = 6 / 6
>> s = 1
Combine like terms. remember to keep the signs.
5x² - 2x² = 3x²
3x - (-6x) = 3x + 6x = 9x
4 - (-3) = 7
3x² + 9x + 7 = Ax² + Bx + C
9 = B, because 9 is in the B's place
9 is your answer
hope this helps