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2 years ago

How do I write 435 in expanded from

Mathematics

1 answer:

SVEN [57.7K]2 years ago

4 0

Answer : 400 + 30 + 5

Step - by - step explanation : To write something in expanded form means to write the number individually. " To see the math value of individual digits ".

4 --> Since it's in the hundreds place that means the number is 400 !

3 --> Since it's in the tenths place that means the number is 30 !

5 --> Since it's the first digit that means it stays as the number 5 !

Hope this helped ! <33

Take care happy holidays ! Contact me if you need more help on this ! ( If you want )

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Miguel has already put 36 sports cards in 5 folders. He buys 372 more cards. He puts the same number of cards into the 5 folders

Ainat [17]

I think the answer is 75.6 because i divided 36 cards by 5 folders and i got 1.2. And then i divided 372 extra cards by 5 folders am got 74.4. I add the two total and have 75.6 5/36 = 1.2 5/372 = 74.4 1.2+74.4= 75.6 srry if I'm wrong

4 0

3 years ago

find the values of the six trigonometric functions for angle theta in standard position if a point with the coordinates (1, -8)

frutty [35]

Answer:

cosФ = $\frac{1}{\sqrt{65}}$ , sinФ = $-\frac{8}{\sqrt{65}}$ , tanФ = -8, secФ = $\sqrt{65}$ , cscФ = $-\frac{\sqrt{65}}{8}$ , cotФ = $-\frac{1}{8}$

Step-by-step explanation:

If a point (x, y) lies on the terminal side of angle Ф in standard position, then the six trigonometry functions are:

cosФ = $\frac{x}{r}$
sinФ = $\frac{y}{r}$
tanФ = $\frac{y}{x}$
secФ = $\frac{r}{x}$
cscФ = $\frac{r}{y}$
cotФ = $\frac{x}{y}$

Where r = $\sqrt{x^{2}+y^{2} }$ (the length of the terminal side from the origin to point (x, y)

You should find the quadrant of (x, y) to adjust the sign of each function

∵ Point (1, -8) lies on the terminal side of angle Ф in standard position

∵ x is positive and y is negative

→ That means the point lies on the 4th quadrant

∴ Angle Ф is on the 4th quadrant

∵ In the 4th quadrant cosФ and secФ only have positive values

∴ sinФ, secФ, tanФ, and cotФ have negative values

→ let us find r

∵ r = $\sqrt{x^{2}+y^{2} }$

∵ x = 1 and y = -8

∴ r = $\sqrt{x} \sqrt{(1)^{2}+(-8)^{2}}=\sqrt{1+64}=\sqrt{65}$

→ Use the rules above to find the six trigonometric functions of Ф

∵ cosФ = $\frac{x}{r}$

∴ cosФ = $\frac{1}{\sqrt{65}}$

∵ sinФ = $\frac{y}{r}$

∴ sinФ = $-\frac{8}{\sqrt{65}}$

∵ tanФ = $\frac{y}{x}$

∴ tanФ = $-\frac{8}{1}$ = -8

∵ secФ = $\frac{r}{x}$

∴ secФ = $\frac{\sqrt{65}}{1}$ = $\sqrt{65}$

∵ cscФ = $\frac{r}{y}$

∴ cscФ = $-\frac{\sqrt{65}}{8}$

∵ cotФ = $\frac{x}{y}$

∴ cotФ = $-\frac{1}{8}$

8 0

3 years ago

Test plz help thank if you help me

zimovet [89]

Answer:

I think its B

Step-by-step explanation: I'm not 100% sure

3 0

3 years ago

A helicopter is hovering 110 feet in the air over a landing pad. If a man sees the helecopter at an angle of elevation of 29°, w

Pavel [41]

See the attached figure to better understand the problem

we know that

tan 29°=AC/CB--------> CB=AC/tan 29°
AC=110 ft
CB--------> <span>how far the man is from the helicopter landing pad
</span>so
CB=AC/tan 29°----------> CB=110/ tan 29°----------> CB=198.45 ft

the answer is
the man is 198.45 ft from the helicopter landing pad

3 0

3 years ago

66.21 was rounded to 2dp. what is the lower bound?

sladkih [1.3K]

Answer:

the answer is 66.205

Step-by-step explanation:

basically you look at the place value so

66.21 is basically the same as 66.210 then you look at the lowest number that can round UP to 66.210 which would be out of 1 to 9 would be 5 so the smallest number that can round up to 66.210 is 66.205 hope this helped :D

4 0

3 years ago