Answer:
z(max) = 256000 Php
x₁ = 10
x₂ = 110
Step-by-step explanation:
Jogging pants design Selling Price Cost
weekly production
Design A x₁ 2500 1750
Design B x₂ 2100 1200
1. z ( function is : )
z = 2500*x₁ + 2100*x₂ to maximize
First constraint weekly production
x₁ + x₂ ≤ 120
Second constraint Budget
1750*x₁ + 1200*x₂ ≤ 150000
Then the model is
z = 2500*x₁ + 2100*x₂ to maximize
Subject to
x₁ + x₂ ≤ 120
1750*x₁ + 1200*x₂ ≤ 150000
General constraints x₁ ≥ 0 x₂ ≥ 0 both integers
First table
z x₁ x₂ s₁ s₂ cte
1 -2500 -2100 0 0 0
0 1 1 1 0 = 120
0 1750 1200 0 1 = 150000
Using AtoZmath online solver and after 6 iterations the solution is:
z(max) = 256000 Php
x₁ = 10
x₂ = 110
Answer:
Farmer Anne's land = 173 acres
Farmer Cassius = 519 acres
Farmer Mel = 1,557 acres
Step-by-step explanation:
Total acre = 2,249
Let
Farmer Anne's land = x
Farmer Cassius = 3x
Farmer Mel = 3(3x) = 9x
x + 3x + 9x = 2,249
13x = 2,249
x = 173
Farmer Anne's land = x = 173 acres
Farmer Cassius = 3x
= 3(173)
= 519 acres
Farmer Mel = 3(3x) = 9x
= 9(173)
= 1,557 acres
Therefore,
Farmer Anne's land = 173 acres
Farmer Cassius = 519 acres
Farmer Mel = 1,557 acres
Answer:
1074.5 or 1074 1/2
Step-by-step explanation:
To justify the yearly membership, you want to pay at least the same amount as a no-membership purchase, otherwise you would be losing money by purchasing a yearly membership. So set the no-membership cost equal to the yearly membership cost and solve.
no-membership costs $2 per day for swimming and $5 per day for aerobic, in other words, $7 per day. So if we let d = number of days, our cost can be calculated by "7d"
a yearly membership costs $200 plus $3 per day, or in other words, "200 + 3d"
Set them equal to each other and solve:
7d = 200 + 3d
4d = 200
d = 50
So you would need to attend the classes for at least 50 days to justify a yearly membership. I hope that helps!
