1. Quadrilateral MNQP is a parallelogram.
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We only need to find the heights of the 2 points on the flagpole and then subtract them. We have that AC and DC are related by the following trigonometric number: tan60=AC/DC. This is because ADC is a right triangle and AC is the opposite leg of the angle we know, while DC is the adjacent leg.
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Thus, we have calculated AC. The same remarks apply to the triangle BCD; However, now we get that tan30=BC/DC.
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Hence, the height of point B is 5 feet, while the height of point A is 15 feet. Their distance is 10 feet.
Thus, we have calculated AC. The same remarks apply to the triangle BCD; However, now we get that tan30=BC/DC.
Hence, the height of point B is 5 feet, while the height of point A is 15 feet. Their distance is 10 feet.