What is the vertex of f(x) = |x + 8|

A submarine lies 3 kilometers from the path of a target ship. The sub’s torpedoes have a range of 5 kilometers. For what distanc

aev [14]

The distance along the path of the ship be within the range of the torpedoes is 4 kilometers.

Explanation:

The submarine lies 3 km from the target ship.

Let B denotes the target ship and C denotes the submarine.

Let AC denotes the the target ship would be within the range of the torpedoes.

The image attached below illustrates that the distance between submarine and the target ship and the range of the torpedoes.

Let BC denotes the distance between the target ship and the submarine. Let AC denotes the range of the torpedoes.

To determine the length of AB, let us use Pythagorean theorem,

$AC^{2} =AB^{2} +BC^{2}$

Substituting the values of BC = 3 and AC = 5, we have,

$5^{2} =AB^{2} +3^{2}$

Squaring the terms, we get,

$25 =AB^{2} +9$

Subtracting both sides by 9, we have,

$16 =AB^{2}$

Taking square root on both sides,

$AB = 4$

Thus, the distance along the path of the ship be within the range of the torpedoes is 4 kilometers.

5 0

4 years ago

Line a is represented by the equation y=−2x+3 .

BartSMP [9]

The second line of eauation y=-2x+5 is parallel to a since both have the same slope which is -
-2
the first line of equation y=2x-1 is neither perpendicular nor parallel to a since the (slope of this line) x (the slope of a) = 2 x -2 = -4 not -1, so they aren't perpendicular and its slope isn't equal to that of a, so they aren't parallel
the last line of equation y=1/2x+7 is perpendicular to a since (the slope of a) x (the slope of this line) = -2 x 1/2 = -1

5 0

3 years ago

Read 2 more answers

Simplest form of 4500:80000 and 8100:144000

a_sh-v [17]

9514 1404 393

Answer: