Answer:
<em>For 10 visits, both gyms charge the same</em>
Step-by-step explanation:
<u>Equations</u>
Gym memberships' costs are:
G1 = 100 + 2x
G2 = 12x
Where x is the number of visits to the gym.
We need to find the number of visits for which the charges for both gyms are the same. Thus equating the costs:
12x = 100 + 2x
Subtracting 2x:
10x = 100
Dividing by 10:
x =10
For 10 visits, both gyms charge the same
Answer:
Infinitely Many Solutions
Step-by-step explanation:
Given
Required
Determine the type of solution
From the matrix, we have:
3 non-zero rows and 5 variables (the last column is the result)
When the number of variables is more than the number of non-zero rows, then such system has infinitely many solutions
i.e.
Answer: $47.06 if you do not round or $47.07 if you are required to round up.
Step-by-step explanation:
$43.99× .07 = 3.0793
$43.99+ $3.07 = $47.06
(If you round up then follow below)
$43.99× .07= 3.0793 (the 9 would cause you to round the 7 up to 8)
$43.99+ $3.08= $47.07
Answer:
1. True
2. False
3. True
4. False
5. True
Step-by-step explanation:
1. For a real number a, a + 0 = a.
This is true, any number plus zero is that number.
2. For a real number a, a + (-a) = 1.
This is false. Adding a negative number is the same as subtracting that number. So a + (-a) = a - a = 0
3. For a real numbers a and b la-bl = |b-al.
This is true. Absolute value represents the distance between two numbers. This number can never be negative, therefore la-bl = |b-al.
4. For real numbers a, b, and c, a +(bº c) = (a + b)(a + c).
False. a + (b * c) = a + bc.
If you foil (a + b)(a + c) you will see its equal to a²+ab+ac+bc, which is definitely different than a + (b*c)
5. For rational numbers a and b when b# o, is always a rational number.
True, a rational number is one that can be written as a fraction with two integers. The quotient of two rational numbers can always be written as a fraction with integers.