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monitta
3 years ago
11

Three siblings- Kate, Sarah, and Dave comitted themselves to volunteer 160 hours for a homeless charity to build new housing. Da

ve worked 15 hours more than Kate. Sarah worked 20 hours fewer than Kate. How many hours did each of these siblings volunteer?
Mathematics
1 answer:
MAXImum [283]3 years ago
4 0

Answer:

Kate 55 hours

Dave 70 hours

Sarah 35 hours

Step-by-step explanation:

Let k be Kate's hours

Dave = 15 + k

Sarah = k- 20

Dave + Kate + Sarah = 160

15 + k + k + k - 20 = 160

3k - 5 = 160

3k = 165

k = 55

Kate worked 55 hours

Dave worked 70 hours

Sarah worked 35 hours

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\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$15000\\
r=rate\to 4.95\%\to \frac{4.95}{100}\to &0.0495\\
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\begin{array}{llll}
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\end{cases}
\\\\\\
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b)

\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$15000\\
r=rate\to 4.95\%\to \frac{4.95}{100}\to &0.0495\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{365 days, thus}
\end{array}\to &365\\
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\end{cases}
\\\\\\
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c)

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A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
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\begin{array}{llll}
\textit{times it compounds per year}\\
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\end{array}\to &4\\
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\end{cases}
\\\\\\
A=15000\left(1+\frac{0.0495}{4}\right)^{4\cdot 1}
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