Sector area= theta/360 x πr^2
Radius= 24/2= 12
Sector area= 120/360 x π(12)^2
Final answer :
Sector area = 48π
Answer:
Step-by-step explanation:
Given that
To find tangent, normal and binormal vectors at (0,0,1)
i) Tangent vector
At the particular point, r'(t) = (1,1,e)
Tangent vector = 
ii) Normal vector
T'(t) = 
At that point T'(t) = (0,0,e)/e = (0,0,1)
iii) Binormal
B(t) = TX N
= ![\left[\begin{array}{ccc}i&j&k\\1&1&e^t\\0&0&e^t\end{array}\right] \\= e^t(i-j)](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Di%26j%26k%5C%5C1%261%26e%5Et%5C%5C0%260%26e%5Et%5Cend%7Barray%7D%5Cright%5D%20%5C%5C%3D%20e%5Et%28i-j%29)
You need to add 38 and 14 together to get answer of 52 years old.
Answer:
100
Step-by-step explanation:
First we find the mean of this set of data. We find the mean by finding the sum of data values and dividing it by the number of data values:
5+10+10+10+10+10+10+15 = 80
There are 8 data values; 80/8 = 10. The mean is 10.
To find the standard deviation, subtract the mean from each value; square the difference; add the squares; divide by the number of data values; and take the square root:
5-10 = -5; 10-10 = 0; 10-10 = 0; 10-10 = 0; 10-10 = 0; 10-10 = 0; 10-10 = 0; 15-10 = 5
(-5)^2 = 25; 0^2 = 0; 0^2 = 0; 0^2 = 0; 0^2 = 0; 0^2 = 0; 0^2 = 0; 5^2 = 25
25+0+0+0+0+0+0+25 = 50
50/8 = 6.25
√6.25 = 2.5
The standard deviation is 2.5.
This means two standard deviations, or 2σ, is 2(2.5) = 5.
This gives us μ-2σ = 10-5 = 5 and μ+2σ = 10+5 = 15.
Since all of our data is between 5 and 15, 100% is within two standard deviations of the mean.
