Answer:
(C) f’(c) = 0 and f”(c) > 0
Step-by-step explanation:
A minimum occurs where the first derivative is 0 (the tangent line is horizontal), and the second derivative is positive (concave up). The simplest example of this is a positive parabola, like y = x², which has a relative minimum at its vertex.
266.605 is the answer.
Step-by-step explanation:
70.6 + 74.02 + 121.985 = 266.605
Answer:
The average value of 
over the interval ![[-2,5]](https://tex.z-dn.net/?f=%5B-2%2C5%5D)
is 
.
Step-by-step explanation:
Let suppose that function is continuous and integrable in the given intervals, by integral definition of average we have that:
(1)
(2)
By Fundamental Theorems of Calculus we expand both expressions:
(1b)
(2b)
We obtain the average value of over the interval ![[-2, 5]](https://tex.z-dn.net/?f=%5B-2%2C%205%5D)
by algebraic handling:
![F(5) - F(3) +[F(3)-F(-2)] = 40 + (-30)](https://tex.z-dn.net/?f=F%285%29%20-%20F%283%29%20%2B%5BF%283%29-F%28-2%29%5D%20%3D%2040%20%2B%20%28-30%29)
The average value of over the interval is .
Answer:
107/21
Step-by-step explanation:
re - phrase the question algebraically:
-14/3 + y = 3/7
LCM of 3 and 7 = 21
-98/21 + y = 9/21
what should be added to -98 to make 9?
answer: 107
therefore answer: 107/21
Hope this helps.
Good Luck
Step-by-step explanation:
First, distribute the -4 to the parenthesis:
24a-22=-4+24a
Add 22 to both sides:
24a-22+22=-4+22+24a
Simplify:
24a=18+24a
Subtract 24a from both sides:
24a-24a=18+24a-24a
Simplify:
0=18
hope this helps :)
