Which of the following is the graph of the quadratic function y=x^2-6x-16

Find the side length of each irregular polygon.

Burka [1]

Answer:

Step-by-step explanation:

Polygon #1

40 + 33 + 23 + 25 + 30 = 151 ft

CD = 175 - 151 = 24 ft

Polygon #2

65 + 57 + 66 = 188 ft

SV = 259 - 188 = 71 ft

I hope I helped you.

4 0

4 years ago

7. What is the next fraction in each of the following patterns?

serious [3.7K]

Answer:

36/40, 47/101, 192

Step-by-step explanation:

(a)The numerator (top number of the fraction) is adding up by odd numbers in order.

From 1/40 to 4/40 you add 3, from 4/40 to 9/40 you add 5, from 9/40 to 16/40 you add 7, and from 16/40 to 25/40 you add 9.

The next number to add would logically be 11. So from 25/40 you would go to 36/40.

36/40 is your next fraction.

(b)

3+4=7,4+7=11,7+11=18,11+18=29,18+29=47

(c) 1*2=2,2*2=4,2*4=8,4*8=32,8*32=256,32*256=8,192

4 0

3 years ago

A fabric manufacturer believes that the proportion of orders for raw material arriving late isp= 0.6. If a random sample of 10 o

ryzh [129]

Answer:

a) the probability of committing a type I error if the true proportion is p = 0.6 is 0.0548

b)

- the probability of committing a type II error for the alternative hypotheses p = 0.3 is 0.3504

- the probability of committing a type II error for the alternative hypotheses p = 0.4 is 0.6177

- the probability of committing a type II error for the alternative hypotheses p = 0.5 is 0.8281

Step-by-step explanation:

Given the data in the question;

proportion p = 0.6

sample size n = 10

binomial distribution

let x rep number of orders for raw materials arriving late in the sample.

(a) probability of committing a type I error if the true proportion is p = 0.6;

∝ = P( type I error )

= P( reject null hypothesis when p = 0.6 )

= ³∑ $_{x=0$ b( x, n, p )

= ³∑ $_{x=0$ b( x, 10, 0.6 )

= ³∑ $_{x=0$ $\left[\begin{array}{ccc}10\\x\\\end{array}\right]$ $(0.6)^x$ $( 1 - 0.6 )^{10-x$

∝ = 0.0548

Therefore, the probability of committing a type I error if the true proportion is p = 0.6 is 0.0548

b)

the probability of committing a type II error for the alternative hypotheses p = 0.3

β = P( type II error )

= P( accept the null hypothesis when p = 0.3 )

= ¹⁰∑ $_{x=4$ b( x, n, p )

= ¹⁰∑ $_{x=4$ b( x, 10, 0.3 )

= ¹⁰∑ $_{x=4$ $\left[\begin{array}{ccc}10\\x\\\end{array}\right]$ $(0.3)^x$ $( 1 - 0.3 )^{10-x$

= 1 - ³∑ $_{x=0$ $\left[\begin{array}{ccc}10\\x\\\end{array}\right]$ $(0.3)^x$ $( 1 - 0.3 )^{10-x$

= 1 - 0.6496

= 0.3504

Therefore, the probability of committing a type II error for the alternative hypotheses p = 0.3 is 0.3504

the probability of committing a type II error for the alternative hypotheses p = 0.4

β = P( type II error )

= P( accept the null hypothesis when p = 0.4 )

= ¹⁰∑ $_{x=4$ b( x, n, p )

= ¹⁰∑ $_{x=4$ b( x, 10, 0.4 )

= ¹⁰∑ $_{x=4$ $\left[\begin{array}{ccc}10\\x\\\end{array}\right]$ $(0.4)^x$ $( 1 - 0.4 )^{10-x$

= 1 - ³∑ $_{x=0$ $\left[\begin{array}{ccc}10\\x\\\end{array}\right]$ $(0.4)^x$ $( 1 - 0.4 )^{10-x$

= 1 - 0.3823

= 0.6177

Therefore, the probability of committing a type II error for the alternative hypotheses p = 0.4 is 0.6177

the probability of committing a type II error for the alternative hypotheses p = 0.5

β = P( type II error )

= P( accept the null hypothesis when p = 0.5 )

= ¹⁰∑ $_{x=4$ b( x, n, p )

= ¹⁰∑ $_{x=4$ b( x, 10, 0.5 )

= ¹⁰∑ $_{x=4$ $\left[\begin{array}{ccc}10\\x\\\end{array}\right]$ $(0.5)^x$ $( 1 - 0.5 )^{10-x$

= 1 - ³∑ $_{x=0$ $\left[\begin{array}{ccc}10\\x\\\end{array}\right]$ $(0.5)^x$ $( 1 - 0.5 )^{10-x$

= 1 - 0.1719

= 0.8281

Therefore, the probability of committing a type II error for the alternative hypotheses p = 0.5 is 0.8281

3 0

3 years ago

What is the Gcf of the number below

never [62]

9514 1404 393

Answer:

b. 60

Step-by-step explanation:

The list of factors is 2, 3, 5, 7. The list of common factors is 2, 3, 5. The lowest exponents on those factor are ...

2^2 × 3^1 × 5^1 = 60

The GCF of 720 and 2100 is 60.

_____

<em>Additional comment</em>

You can verify this using Euclid's method of finding the GCF.

2100/720 = 2 r 660

720/660 = 1 r 60

660/60 = 11 r 0 . . . . 60 is the GCF

Find the remainder from the division. If it is zero, the divisor is the GCF. If it is non-zero, replace the largest number with the remainder, and repeat.

7 0

3 years ago

Which list shows these lengths in order from greatest to least?

finlep [7]

9514 1404 393

Answer:

√3/11, π/24, 3/25, 9/100

Step-by-step explanation:

The 2-decimal value of each of the numbers is ...

9/100 = 0.09

π/24 = 0.13

3/25 = 0.12

√3/11 = 0.16

Then the order from greatest to least is 0.16, 0.13, 0.12, 0.09. In the original form, that is ...

√3/11, π/24, 3/25, 9/100 . . . . . matches choice B

8 0

3 years ago