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2 years ago

5

A graphing calculator is recommended. For the limit lim x → 3 (x3 − 4x + 3) = 18 illustrate the definition by finding the larges

t possible values of δ that correspond to ε = 0.2 and ε = 0.1. (Round your answers to four decimal places.) ε = 0.2 δ = ε = 0.1 δ =

1 answer:

alexira [117]2 years ago

6 0

Answer:

Attached is the detailed solution of the problem

∈ = 0.0081 ≈ 0.2

∈ = 0.0042 ≈ 0.1

Step-by-step explanation:

Attached is the detailed solution of the problem

∈ = 0.0081 ≈ 0.2

∈ = 0.0042 ≈ 0.1

A graphing calculator recommended was used to arrive at this solution

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Tpy6a [65]

Answer:

x=0

Step-by-step explanation:

0-0=0

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3 years ago

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If you pay $3 to enter the farm and $2.50 per pound for the berries you pick. Write an equation to model the total cost, y, for

sweet [91]

The answer is 3+2.50x=y

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2 years ago

Elza [17]

Answer:

$(b)\ 2x - 9 = -1$

$(c)\ -2x + 12 = 4$

$(e)\ 2(x - 10) = -12$

Step-by-step explanation:

Required

Which equals $x = 4$

$(a)\ 2x + 6 = 2$

Collect like terms

$2x = 2 - 6$

$2x = -4$

Divide both sides by 2

$x = -2$

$(b)\ 2x - 9 = -1$

Collect like terms

$2x = -1 + 9$

$2x = 8$

Divide both sides by 2

$x = 4$

$(c)\ -2x + 12 = 4$

Collect like terms

$-2x =- 12 + 4$

$-2x =-8$

Divide both sides by -2

$x = 4$

$(d)\ 2(x + 2) = 10$

Divide both sides by 2

$x + 2 =5$

Collect like terms

$x = 5-2$

$x = 3$

$(e)\ 2(x - 10) = -12$

Divide both sides by 2

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Hence, the equations with the required solution are:

$(b)\ 2x - 9 = -1$

$(c)\ -2x + 12 = 4$

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2 years ago

The grade appeal process at a university requires that a jury be structured by selecting six individuals randomly from a pool of

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Answer: a) $\dfrac{3}{874}$

b) $\dfrac{30}{3059}$

c) $\dfrac{3575}{12236}$

Step-by-step explanation:

Given : Number of students : 11

Number of faculty members : 13

Total persons : $11+13=24$

Total number of ways to structure a jury of six people from a group of 24 people :-

$^{24}C_{6}=\dfrac{24!}{6!(24-6)!}=134596$

a) Number of ways of selecting a jury of all students :-

$^{11}C_{6}=\dfrac{11!}{6!(11-6)!}=462$

Then , the probability of selecting a jury of all students :-

$\dfrac{462}{134596}=\dfrac{3}{874}$

b) Number of ways of selecting a jury of all faculty :-

$^{13}C_{6}=\dfrac{13!}{6!(13-6)!}=462$

Then , the probability of selecting a jury of all students :-

$\dfrac{1716}{134596}=\dfrac{30}{3059}$

c) Number of ways of selecting a jury of two students and four faculty :-

$^{11}C_{2}\times^{13}C_{4}=\dfrac{11!}{2!(11-2)!}\times\dfrac{13!}{4!(13-4)!}=39325$

Then , the probability of selecting a jury of all students :-

$\dfrac{39325}{134596}=\dfrac{3575}{12236}$

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2 years ago

What is the inverse of f(x)=2(x+4)²-5

olchik [2.2K]

I would be <em> $2x^{2} +16x+27$ </em>

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2 years ago