In order to solve or know the probability of having 2 girls
and 2 boys, assumed that a girl is as likely as a girl at each birth, pascal’s
triangle will be likely used. And we will be referring to the line 4 of pascal’s
triangle, which was 1 4 6 4 1. Then it
will look like this: 1 = 4 girls; 4 = 3 girls & 1 boy; 6 = 2 girls & 2
boys; 4 = 3 boys & 1 girl; 1 = 4 boys. And now for the solution in order to
get the probability of having 2 girls and 2 boys is to divided into the sum of 1+4+6+4+1.
First we have to know the formula of the volume f each of the solids,
<span>V of sphere = 4/3 pi r^3
</span><span>Volume of Cylinder = pi r^2(2r)=2pi r^3
</span><span>Volume of cone = 1/3 pi r^2(r)=1/3 pi r^3
</span>
The surest and easiest way we can answer this is actually assigning values. We first assign values to r hence we would get the volume of the sphere and rest of the solids (cylinder and cone). You then compare your answers to that of the sphere, and you should get your answer.
(7-11) • (5) = -20
A. (5) • 7 + (5) • (-11)
↳ 35 + (-55)
↳ 35 - 55 = -20
B. -(-7+11) • (5)
↳ -4 • 5 = -20
C. (5) • 7 - (5) • 11
↳ 35 - 55 = -20
D. (7+11) • (5)
↳ 18 • 5 = 90
A B & C are correct
Angle MNO is 90, it’s just the top right corner