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Tju [1.3M]
3 years ago
6

What is the next number on sequence 2 7 8 3 12 9

Mathematics
1 answer:
Kamila [148]3 years ago
8 0
The term of this sequence is: 
<span>-(17/30)n^5+(113/12)n^4-(173/3)n^3+(1915/12)n^2-(5813/30)n+85 </span>
<span>Therefore,term number 7 is:-146/1=-146 </span>
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Which step is the mistake in 1 or 2?
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Answer:

1 is the mistake

Step-by-step explanation:


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You want to enlarge the picture by a factor of 4 from its current size of 5 inches by 7 inches what is the size of the enlarged
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Answer:

20 inches by 28 inches

Step-by-step explanation:

The current size of the picture is 5 inches by 7 inches

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use the definition of countinuity to find the value of k so that the function is continuous for all real numbers
liubo4ka [24]

First of all, recall the definition of absolute value:

|x| = \begin{cases}x&\text{if }x\ge0\\-x&\text{if }x

So if <em>x</em> < 4, then <em>x</em> - 4 < 0, so |<em>x</em> - 4| = -(<em>x</em> - 4), and the first case in <em>h(x)</em> reduces to

\dfrac{|x-4|}{x-4}=\dfrac{-(x-4)}{x-4} = -1

Next, in order for <em>h(x)</em> to be continuous at <em>x</em> = 4, the limits from either side of <em>x</em> = 4 must be equal and have the same value as <em>h(x)</em> at <em>x</em> = 4. From the given definition of <em>h(x)</em>, we have

h(4) = 5k-4\cdot4 = 5k-16

Compute the one-sided limits:

• From the left:

\displaystyle \lim_{x\to4^-}h(x) = \lim_{x\to4}\frac{|x-4|}{x-4} = \lim_{x\to4}(-1) = -1

• From the right:

\displaystyle \lim_{x\to4^+}h(x) = \lim_{x\to4}(5k-4x) = 5k-16

If the limits are to be equal, then

-1 = 5<em>k</em> - 16

Solve for <em>k</em> :

-1 = 5<em>k</em> - 16

15 = 5<em>k</em>

<em>k</em> = 3

3 0
3 years ago
How do I find out 145 lb = __ kg
zmey [24]
145 Ib= 65.7709kg
you can find the answer on google also they have a calculator for that if u have anymore questions like this just type in 145 Ib=__kg and it will pop up
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