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2 years ago

6

What is the next number on sequence 2 7 8 3 12 9

1 answer:

Kamila [148]2 years ago

8 0

The term of this sequence is:
<span>-(17/30)n^5+(113/12)n^4-(173/3)n^3+(1915/12)n^2-(5813/30)n+85 </span>
<span>Therefore,term number 7 is:-146/1=-146 </span>

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Help guysss im in 6th really need help

NNADVOKAT [17]

5 times as many. Since dog B has 2 and dog A has 10, A = 2 * X, since you’re solving for the multiplication comparison. 10/2 = 5, so you’ve got 5 times as many.

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2 years ago

Pls help with this thx

Natalija [7]

1. 55
2. N/A - Sorry. I can’t see the numbers properly.
3. 180

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2 years ago

Which graph shows f(x) = |x| reflected across the x-axis, translated 2 units down and 1 unit to the left?

Reptile [31]

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Cuánto le falta a 3/5para llegar a 9/10

Bumek [7]

Answer:

3/10

Step-by-step explanation:

3/5 se puede convertir en 6/10

(3x2)/(5x2).

9/10 - 6/10 = 3/10

le falta 3/10 para llegar a 9/10.

7 0

2 years ago

A mixture of compounds X and Y in a 0.100-cm cell had an absorbance of 0.215 at 272 nm and 0.191 at 327 nm. Find [X] and [Y] in

Oksi-84 [34.3K]

Answer: The concentration of X is $7.13582\times 10^{-6}$ and the concentration of Y is $2.53159\times 10^{-5}$ .

Step-by-step explanation:

Since we have given that

At 272 nm, absorbance = 0.215

At 327 nm, absorbance = 0.191

As we have given that

Compound X Compound Y

272 16400 3870

327 3990 6420

So, our equations becomes

$16400C_1+3870c_2=0.215\\\\3990C_1+6420C_2=0.191$

By solving these two equations, we get that

$C_1=7.13582\times 10^{-6}\\\\C_2=2.53159\times 10^{-5}$

Hence, the concentration of X is $7.13582\times 10^{-6}$ and the concentration of Y is $2.53159\times 10^{-5}$ .

5 0

3 years ago