D............ .... . . . . . . . . . . . . . . . . . . . .
Answer: Twice the previous time would be taken to reach the same speed v with the puck of mass 2m.
Explanation:
Let a Force pushes the hockey puck of mass m.
Then acceleration, a= \frac{F}{m}a=mF
From the equation of motion,
\begin{gathered}\➪ v=u+at\\ v=0+\frac{F}{m}\Delta t\end{gathered}⇒v=u+atv=0+mFΔt ......(1)
In the second case, when mass is 2m, then acceleration,
a'=\frac{F}{2m}a′=2mF
and t' is the time taken.
The final speed is v,
\begin{gathered}\➪ v=0+ a't'\\ \➪ \frac {F}{m}\Delta t=\frac{F}{2m}t'\\ \➪ t'= 2\Delta t\end{gathered}⇒v=0+a′t′⇒mFΔt=2mFt′⇒t′=2Δt using equation (1)
Hence, it would take two times the previous amount of time to push the pluck of double mass.
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Answer:
1. angle addition postulate 2. of the triangle theorem 3. subtraction property
Explanation:
i got it right on edge ma dudes
The value of s that will be able to yield the coordinate (4, 3) is 5.
<h3>How to find the value?</h3>
From the information given, in order to find the value of s, we'll use the Pythagoras theorem. This goes thus:
OA = ✓4² + ✓3²
OA = ✓(16 + 9)
OA = ✓25
OA = 5
Therefore, value of s that will be able to yield the coordinate (4, 3) is 5.
Learn more about coordinate on:
brainly.com/question/17206319
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