170% converted to a fraction equals.

Find the interval(s) on which the function is increasing.

Tatiana [17]

Answer:

II (THE Second one )

Step-by-step explanation:

Because when you substitute X by (-2)

you will get :

y=(-2)^2 - 6(-2) - 16 = Zero

So, -2 is not including in the interval .

4 0

3 years ago

Read 2 more answers

You can make a tent by throwing a piece of cloth over a clothesline, then securing the edge to the ground with stakes so that an

4vir4ik [10]

Based on the required width and height of the tent, the length of the cloth would have to be 14.4 ft.

<h3>How long should the length of the cloth be?</h3>

The opening of the tent would be an isosceles triangle but if it is divided in two from the top, a right-angled triangle will be formed and the hypotenuse will be the length of the cloth on one side.

That length - according to the Pythagoras theorem - would be:

= √(6² + (8 /2)²)

= √(36 + 16)

= 7.2 ft

As this is the length of one side of the cloth, the length of the entire cloth is:

= 7.2 x 2

= 14.4 ft

Find out more on the Pythagoras theorem at brainly.com/question/343682.

#SPJ1

8 0

2 years ago

Centerville is the headquarters of Greedy Cablevision Inc. The cable company is about to expand service to two nearby towns, Spr

NeX [460]

Answer:

20.2057 Units.

Step-by-step explanation:

First, we determine the length of the cable.

Distance between Centerville (8,0) and point (x,0) is given as:

$\sqrt{(8-x)}^2=8-x$

Distance between point (x,0) and Springfield(0,7) is:

$\sqrt{(7-0)^2+(0-x)^{2}}=\sqrt{(7)^2+(x)^{2}}$

Distance between point (x,0) and Shelvyfield(0,-7) is:

$\sqrt{(-7-0)^2+(0-x)^{2}}=\sqrt{(7)^2+(x)^{2}}$

Therefore the Length of the Cable L(x)

$L(x)=(8-x)+2\sqrt{(7)^2+(x)^{2}}$

To find the critical point, we set the derivative of L(x)=0

$L^{'}(x)=-1+\frac{2x}{\sqrt{\left( 49 - x^{2}\right) }}$

$\frac{-\sqrt{\left( 49 - x^{2}\right)}+2x}{\sqrt{\left( 49 - x^{2}\right)}}=0\\-\sqrt{\left( 49 - x^{2}\right)}+2x=0\\\sqrt{\left( 49 - x^{2}\right)}=2x\\(\sqrt{\left( 49 - x^{2}\right)})^2=(2x)^2\\49 - x^{2}=4x^2\\49=5x^2\\x^2=\frac{49}{5}\\x= 3.1305$

To verify that L(x) has a minimum at this critical number we compute the second derivative L″(x) and find its value at the critical number.

$L^{''}(x)=\frac{\left( 98\right) \,\sqrt{\left( 49 - x^{2}\right) }}{{\left( 7 - x\right) }^{2}\,{\left( 7+x\right) }^{2}}\\At \:x=3.1305, L^{''}=0.3993$

Since $L^{''}(x)$ is positive, the minimum point of L(x) exists.

Next, we find the minimum length by substituting z=3.1305 into L(x)

$L(3.1305)=(8-3.1305)+2\sqrt{(7)^2+(3.1305)^{2}}$

Minimum Length, L=20.2057

The minimum length of the cable is 20.2057 Units.

6 0

3 years ago

A shipping crate contains 576 boxes of cereal. you open the top of the crate and you count 12 boxes across the front and 6 along

alisha [4.7K]

There are 8 layers in the crate!
Our volume is 576 units, or cereal boxes. 576 = 12 × 6 × UNKNOWN.
We can find our unknown number by dividing:
576 ÷ 12 ÷ 6 = 8 layers!
I hope this explained it!

5 0

4 years ago

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What are possible ratios for 16 to 32

Nastasia [14]

Answer:

1:3

Step-by-step explanation:

To simplify the ratio 16:32, we find the greatest common divisor of 16 and 32, and then we divide 16 and 32 by the greatest common divisor.

The greatest common divisor that you can use to simplify 16:32 is 16. Which means the answer to ratio 16:32 simplified is: 1:2

Hope it helps

6 0

2 years ago