Answer:
Step-by-step explanation:
- Mother's age = m
- Son's age = s
<u>3 years later:</u>
- m + 3 = 4(s + 3) ⇒ m = 4s + 12 - 3 = 4s + 9
<u>3 years ago:</u>
- m - 3 = 2(s + 8) ⇒ m = 2s + 18 + 3 = 2s + 21
<u>Solve for s by substitution:</u>
- 4s + 9 = 2s + 21
- 2s = 12
- s = 6
<u>Find the value of m:</u>
Mother is 33 and son is 6
X is your per hour y is the answer itself
Don’t Flush is y= 10x + 50
Fire hole is y= 5x + 90
Answer:
C, never negative
it can be zero in exactly one occasion
When you have 3 choices for each of 6 spins, the number of possible "words" is
3^6 = 729
The number of permutations of 6 things that are 3 groups of 2 is
6!/(2!×2!×2!) = 720/8 = 90
A) The probability of a word containing two of each of the letters is 90/729 = 10/81
The number of permutations of 6 things from two groups of different sizes is
(2 and 4) : 6!/(2!×4!) = 15
(3 and 3) : 6!/(3!×3!) = 20
(4 and 2) : 15
(5 and 1) : 6
(6 and 0) : 1
B) The number of ways there can be at least 2 "a"s and no "b"s is
15 + 20 + 15 + 6 + 1 = 57
The probability of a word containing at least 2 "a"s and no "b"s is 57/729 = 19/243.
_____
These numbers were verified by listing all possibilities and actually counting the ones that met your requirements.
I’m sorry I don’t know the answer to that but maybe if you go in quizlet you can find the answer.