Hello!
To find the line that is perpendicular to y = 3x - 2 and passes through the ordered pair (6, 8), we will:
- Find the negative reciprocal using the slope of the given function
- Substitute the given ordered pair into the new equation with the slope found in step 1
Let's remind ourselves of slope-intercept formula. Slope-intercept formula is y = mx + b, where m is the slope, and b is the y-intercept.
In the given equation, we know that 3 is slope. With that, we can find the negative reciprocal of that slope, and continue to step #2.
To find the reciprocal, we will need to flip our fraction. In this case, 3/1 = 3, so once we flip it, it is 1/3. Since it is the negative reciprocal, the fraction is a negative, so the negative reciprocal is -1/3.
Now, we will substitute the ordered pair into the slope-intercept formula with our new slope.
y = -1/3x + b (6, 8)
8 = -1/3(6) + b
8 = -2 + b (add 2 to both sides)
10 = b
Therefore, the equation of the line is y = -1/3x + 10.
