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4 years ago

|8m| = 104 absolute value

Mathematics

1 answer:

DENIUS [597]4 years ago

6 0

Answer:

m=13

Step-by-step explanation:

l8ml=104

8m=104

⁻⁻⁻ ⁻⁻⁻

8 8

m=13

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Hi! I'm not sure of the answer to this.

andriy [413]

Answer:

y - 2 = (-3/7)(x + 5)

Step-by-step explanation:

Recall that the slopes of a line and another line perpendicular to the first are negative reciprocals.

The slope of the given line is 7/3. The negative reciprocal of that is -3/7. Thus, we immediately eliminate the fourth answer choice.

We must now find the equation of the perpendicular line, with slope -3/7, that passes through (-5, 2). We'll do that using the point-slope formula for the equation of a straight line.

That formula is y - k = m(x - h), where m is the slope and (h, k) is the given point.

Substituting 2 for k, -5 for h and -3/7 for m, we get:

y - 2 = (-3/7)(x + 5). This matches the 3rd given possible answer.

5 0

3 years ago

Find the equation of the line that is perpendicular to the line y =-2 passing through the point(3,4)

masha68 [24]

Answer:

Step-by-step explanation:

x = 3

6 0

3 years ago

Help with this integral<br><br><img src="https://tex.z-dn.net/?f=%20%5Cint%5Climits%20%5Cfrac%7Bdx%7D%7Bx%5E%7B2%7D-4x-13%7D" id

charle [14.2K]

$x^2-4x-13=(x-2)^2-17$

$x-2=\sqrt{17}\sec y$
$\mathrm dx=\sqrt{17}\sec y\tan y\,\mathrm dy$

$\displaystyle\int\frac{\mathrm dx}{x^2-4x-13}=\int\frac{\sqrt{17}\sec y\tan y}{(\sqrt{17}\sec y)^2-17}\,\mathrm dy$
$=\displaystyle\frac1{\sqrt{17}}\int\frac{\sec y\tan y}{\sec^2y-1}\,\mathrm dy$
$=\displaystyle\frac1{\sqrt{17}}\int\frac{\sec y\tan y}{\tan^2y}\,\mathrm dy$
$=\displaystyle\frac1{\sqrt{17}}\int\frac{\sec y}{\tan y}\,\mathrm dy$
$=\displaystyle\frac1{\sqrt{17}}\int\frac{\frac1{\cos y}}{\frac{\sin y}{\cos y}}\,\mathrm dy$
$=\displaystyle\frac1{\sqrt{17}}\int\csc y\,\mathrm dy$
$=-\dfrac1{\sqrt{17}}\ln|\csc y+\cot y|+C$

$\sec y=\dfrac{x-2}{\sqrt{17}}\iff y=\sec^{-1}\dfrac{x-2}{\sqrt{17}}$
$\implies\csc y=\dfrac{x-2}{\sqrt{(x-2)^2-17}}=\dfrac{x-2}{\sqrt{x^2-4x-13}}$
$\implies\cot y=\dfrac{\sqrt{17}}{\sqrt{(x-2)^2-17}}=\dfrac{\sqrt{17}}{\sqrt{x^2-4x-13}}$

$\displaystyle\int\frac{\mathrm dx}{x^2-4x-13}=-\dfrac1{\sqrt{17}}\ln\left|\frac{x-2+\sqrt{17}}{\sqrt{x^2-4x-13}}\right|+C$

6 0

4 years ago

8. bx = c solve for x

mina [271]

For number 8, to solve for x you have to isolate it by dividing both sides of the equation by b. This will give you x=c/b. (Always see if you can do addition/subtraction so you don't get confused and then do multiplication/division. In this case you didn't need to add or subtract anything so you were able to just divide).

For number 9, again you have to isolate the variable p. Start be subtracting kn from both sides of the equation. The operation between m and p is multiplication. The opposite of this is division so divide both sides of the equation by m. Your answer should be p=(q-kn)/m.

For number 10, you're trying to isolate r so start by subtracting b. Now divide both sides by the b next to the r. Your answer should be r=(a-b)/b.

For number 11, you want t by itself so start by subtracting the p that's by itself. Now divide pr from both sides. Your answer should be t=(A-p)/pr.

For number 12, you want y by itself. All you have to do for this one is add b/m to the other side of the equation. Your answer should be y=x+(b/m).

Finally for number 13, you want to isolate p by multiplying both sides of the equation by q. Your answer should be p=q(m/n).

Let me know if you have any questions and I hope this helped!

8 0

3 years ago

Determine the remaining sides and angles of the triangle ABC.

Goryan [66]

Answer:

Angle C ∠C = 160.49°

side b = 0.522 m

side a = 17.34 m

Step-by-step explanation:

Given that;

In a Δ ABC,

∠A = 18.95°