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mojhsa [17]
3 years ago
15

|8m| = 104 absolute value

Mathematics
1 answer:
DENIUS [597]3 years ago
6 0

Answer:

m=13

Step-by-step explanation:

Ok

l8ml=104

8m=104

⁻⁻⁻  ⁻⁻⁻

8        8

m=13

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Solve x^2+20x+100=50
uysha [10]
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</span><span> x^2+20x+50=0
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3 years ago
Romb ma obwód równy 32 cm. Jakie jest pole tego rombu, jeżeli jego wysokość ma 3 cm?
Goshia [24]

Answer:

24 cm²

Step-by-step explanation:

Z zadanego powyżej pytania uzyskano następujące dane:

Obwód (obwód) = 32 cm

Wysokość (h) = 3 cm

Obszar rombu (A) =?

Następnie określimy długość boku rombu. Można to uzyskać w następujący sposób:

Obwód, czyli obwód (P) = 32 cm

Strona (y) =?

P = 4 s

32 = 4 s

Podziel obie strony przez 4

s = 32/4

s = 8 cm

Stąd długość boku rombu wynosi 8 cm

Na koniec określimy obszar rombu w następujący sposób:

Długość boków = 8 cm

Wysokość (h) = 3 cm

Obszar rombu (A) =?

A = sh

A = 8 × 3

A = 24 cm²

Dlatego obszar rombu jest

24 cm².

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Answer:

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