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il63 [147K]
3 years ago
15

Any one have a snnaap chhhaatt if so i need help with something n there

Computers and Technology
2 answers:
choli [55]3 years ago
7 0

I can help through comments as well

kaheart [24]3 years ago
3 0

I will say not all ppl want to share their personal social stuff on here. I can try answering through comments tho

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A researcher plans to identify each participant in a certain medical experiment with a code consisting of either a single letter
trapecia [35]

Answer:

5 Letters

Explanation:

So we need 12 distinct codes made of a single letter or a pair of letters.

What would be the least number of letters?

Lets try with 3 letters A, B and C

The possible combinations are: A, B, C, AB, AC, BC

These are 6 codes and we need 12 so lets try more A, B, C and D

The possible combinations are: A, B, C, D, AB, AC, AD, BC, BD, CD

These are 10 codes and we need 12 so lets try more A, B, C, D and E

The possible combinations are:

A, B, C, D, E, AB, AC, AD, AE, BC, BD, BE, CD, CE, DE

Finally we got 15 distinct codes which are more than 12 so the least number of letters needed are 5.

Using formula:

Four letters = 4C1 + 4C2 = 4 + 6 = 10

Five letters = 5C1 + 5C2 = 5 + 10 = 15

5 0
3 years ago
In a wide area network (WAN), how would you troubleshoot an issue with the domain name system (DNS)?
NISA [10]
<span>C. Get the help of someone with specialized knowledge in the area.</span>
3 0
4 years ago
Read 2 more answers
Write a program that helps a young student learn to make change. Use the random number generator to generate change amounts betw
erastovalidia [21]

Answer:

#include <iostream>

#include <stdlib.h>

using namespace std;

int main()

{

srand(time(0));

 

int coins = rand()%99 + 1;

int temp = coins;

cout<<"Enter the coins needed to make $0."<<coins<<"?"<<endl<<endl;

int a, b, c, d;

cout<<"Quarters? ";

cin>>a;

cout<<"Dimes? ";

cin>>b;

cout<<"Nickles? ";

cin>>c;

cout<<"Pennies? ";

cin>>d;

 

int quarters = coins/25;

 

coins = coins%25;

 

int dimes = coins/10;

 

coins = coins%10;

 

int nickles = coins/5;

coins = coins%5;

 

int pennies = coins/1;

 

if(((a*25) + (b*10) + (c*5) + (d*1))==temp)

{

cout<<"That's correct"<<endl;

 

if(a!=quarters || b!=dimes || c!=nickles || d!=pennies)

{

cout<<"The optimized solution is "<<endl;

}

}

else

{

cout<<"Not correct"<<endl;

cout<<"The solution is "<<endl;

 

}

 

cout<<"\tQuarters: "<<quarters<<endl;

cout<<"\tDimes: "<<dimes<<endl;

cout<<"\tNickles: "<<nickles<<endl;

cout<<"\tPennies: "<<pennies<<endl;

return 0;

}#include <iostream>

#include <stdlib.h>

using namespace std;

int main()

{

srand(time(0));

 

int coins = rand()%99 + 1;

int temp = coins;

cout<<"Enter the coins needed to make $0."<<coins<<"?"<<endl<<endl;

int a, b, c, d;

cout<<"Quarters? ";

cin>>a;

cout<<"Dimes? ";

cin>>b;

cout<<"Nickles? ";

cin>>c;

cout<<"Pennies? ";

cin>>d;

 

int quarters = coins/25;

 

coins = coins%25;

 

int dimes = coins/10;

 

coins = coins%10;

 

int nickles = coins/5;

coins = coins%5;

 

int pennies = coins/1;

 

if(((a*25) + (b*10) + (c*5) + (d*1))==temp)

{

cout<<"That's correct"<<endl;

 

if(a!=quarters || b!=dimes || c!=nickles || d!=pennies)

{

cout<<"The optimized solution is "<<endl;

}

}

else

{

cout<<"Not correct"<<endl;

cout<<"The solution is "<<endl;

 

}

 

cout<<"\tQuarters: "<<quarters<<endl;

cout<<"\tDimes: "<<dimes<<endl;

cout<<"\tNickles: "<<nickles<<endl;

cout<<"\tPennies: "<<pennies<<endl;

return 0;

}

Explanation:

  • Use the built-in rand function to generate a random coin.
  • Get all the required values for quarters, dimes, nickles and pennies and store them in variables.
  • Check if the coins give a value of temp, then answer is correct and the values of user will be added.
  • Optimum solution is displayed  If it does not matches with the optimum solution. Display that the answer is wrong along with solution.
6 0
3 years ago
Circuitry can be either basic or ___________.
Sonja [21]
I think it would be A. Ohm's law.
hope this helps.
6 0
3 years ago
Read 2 more answers
PLEASE CAN ANYBODY ANSWER ANY OF THESE
Pie

16 in Binary is ob10000

32 in Binary ob100000

I'm not sure if those are in 8 bit or not.


6 0
4 years ago
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