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defon
3 years ago
5

If the density of iron is 7.8 g/cm3 and you find an iron nail weighing 15g, what would the volume of the nail be?

Mathematics
2 answers:
erastova [34]3 years ago
8 0
Density =mass/ volume   ⇒ volume=mass/ density

Data:
density=7.8 g/cm³
mass=15 g

volume=15 g/7.8 g/cm³=1.92 cm³

answer., the volume of the nail will be 1.92 cm³
Elena-2011 [213]3 years ago
5 0
117 cm3 is the answer 

Hope it helps 
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You go to a local mechanic to get your tires changed. The tires cost $300. There is a 6% sales tax, but you get a 10% discount.
Romashka-Z-Leto [24]

Answer:

a) T(x)=300x+18x=318x

b) D(x)=318x-(0.1)(318)+10x\\=296.2x

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b) And the total cost after discounts, is then given by:

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6 0
3 years ago
One container is filled with a mixture that is 30%acid a second container is filled with a mixture that is 50%acid the second co
julsineya [31]

Answer:

The amount of acid in third container is =42%

Step-by-step explanation:

Given , one container is filled with a mixture that is 30% acid a second container filled with a mixture that is 50% acid and the second container 50% larger than the first .

Let, the volume of first container is = x

Then , the volume of second container = (x+ x of 50%)

                                                                 = x + 0.5 x

                                                                 = 1.5 x

Therefore the amount of acid in first container =x \times \frac{30}{100} = 0.3 x

The amount of acid in second container =1.5x \times \frac{50}{100}  = 0.75x

Total amount of acid= 0.3x + 0.75x = 1.05 x

Total amount  of solution = x+1.5x = 2.5x

The amount of acid in third container is = \frac{1.05x}{2.5x} \times 100% %

                                                                     = 42%

4 0
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