2 years ago

PLEASE HELP ASAPPPP!!!!!!! here is a screenshot of the math problem

Mathematics

1 answer:

Harlamova29_29 [7]2 years ago

3 0

X = -1 Is the answer hope you get it right!!!!

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Help me please ......

Alja [10]

$2\frac{3}{4}*2=\frac{2*4+3}{4}*2=\frac{11}{4}*2=\frac{22}{4}= 5\frac{2}{4}=5\frac{1}{2}$

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3 years ago

5x+3y>_ 9 <br> ^<br> This sign is supposed to be greater than Or equal to. Sorry.

Andre45 [30]

It’s saying the equation is going to be equal to.

HOPE THIS HELPS

5 0

3 years ago

What algebraic expression represents the phase “two times the quantity of a number minus 12”

MakcuM [25]

Answer:

2(n-12)

Step-by-step explanation:

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3 years ago

I been trying to do this for the past 20 minutes and I don’t understand can someone help please

puteri [66]

Answer:

Step-by-step explanation:

Do substitution by first writing an equation 15c + 29a=175 when you get your answer either substitute it in your other equation which would be 21c+27a=177, if you found c(Children) in your first equation substitute it in 21 by multipying if you found a do the same thing.

4 0

3 years ago

The distance d of a particle moving in a straight line is given by d(t) = 2t3 + 5t – 2, where t is given in seconds and d is mea

Sergeeva-Olga [200]

Answer:

Step-by-step explanation:

Given the distance, d(t) of a particle moving in a straight line at any time t is:

$d(t) = 2t^3 + 5t - 2, $ where t is given in seconds and d is measured in meters.$

To find an expression for the instantaneous velocity v(t) of the particle at any given point in time, we take the derivative of d(t).

$v(t)=\dfrac{d}{dt}\\\\v(t) =\dfrac{d}{dt}(2t^3 + 5t - 2) =3(2)t^{3-1}+5t^{1-1}\\\\v(t)=6t^2+5$

The correct option is C.

6 0

3 years ago