The dimensions are 16 ft by 32 ft
The quadratic equation is w^2-256=0
We have given that,
Todd and his brother Robert are going to use 512 square feet of their backyard for skateboard ramps. the shape of the backyard is rectangular, with the length twice as long as the width.
<h3>What is the area of the rectangle?</h3>
The area of a rectangle is equal to
A=WL
Where L is the long side of the rectangle
W is the width side of the rectangle
in this problem we have
A=512ft^2
S0,512=LW -----> equation A
L=2W ------> equation B
substitute equation B in equation A
512=2W(W)
512=2w^2
2w^2-512=0
W^2=512/2
W=\sqrt(256)
W=16
Find the value of L
L=2W
L=2(16)
L=32ft
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Answer:
y = 2/3x - 1
Step-by-step explanation:
The simpliest way to determine the slope of the line is to see the rise over run of the line. In this case, we are given two points which are at (0, -1) and (3,1)
By calculating rise of run, we can see that the starting point goes up by 2 units, from -1 to 1 and goes to the right 3 units, from 0 to 3
In this case, that means we have a slope of 2/3x.
The +b plays into the y-intercept of the line, which is actually the same of one of our points: (0,-1)
Since this number is a negative, it would actually be y = (2/3)x + (-1) which is the same as y=2/3x - 1
The area, assuming is a rectangular floor, is their product.
so simply convert the mixed to improper and get their product.
