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3 years ago

I hate this, what even is the point of summer school?

SAT

2 answers:

rosijanka [135]3 years ago

5 0

Answer:

Please mark me brainliest

Explanation:

nasty-shy [4]3 years ago

3 0

Answer:there is no point

Explanation:

Because there I no point

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I need help with this problem plz do not cheap out on this and i swear to god if u do it just for the points *&^&*%$#%^&

erastova [34]

Answer:

I think maybe C or D

Explanation:

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3 years ago

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The math department at a small school has 5 teachers. The ages of these teachers are 23, 34, 37, 42, and 58. Suppose you select

denis23 [38]

The graph that shows the sampling distribution of the sample minimum age is; Option C Graph

<h3>Sampling distribution</h3>

We are given the ages of the 5 teachers as;

23, 34, 37, 42 and 58.

The options that show the sampling distribution of the sample minimum age has been attached.

Since 4 teachers will be selected out of the 5, it means that the minimum age of the 4 selected teachers will be 23 years of age 4 time while the minimum age will be 34 if the 23 year old teacher is not selected.

In conclusion, the sampling distribution for this scenario of minimum age should show 4 teachers at the 23 year mark and 1 teacher at the 34 year mark.

Read more about sampling distribution at; brainly.com/question/15077367

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2 years ago

Why is it necessary for us to compute your purchases

Dafna11 [192]

It is important to calculate discounts independently to ensure that each discount is applied to the price of each product. ... It is also important to calculate them to know the real total price of the purchase you are going to make.

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2 years ago

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company manufactured six television sets on a given day, and these TV sets were inspected for being good or defective. The resul

lana [24]

Sampling distribution involves the proportions of a data element in a given sample.

The proportion of Good TV set is 0.67
The number of ways of selecting 5 from 6 TV sets is 6
The number of ways of selecting 4 from 6 TV sets is 15

Given

$n = 6$

Sample Space = Good, Good, Defective, Defective, Good, Good

(a) Proportion that are good

From the sample space, we have:

$Good = 4$

So, the proportion (p) that are good are:

$p = \frac{Good}{n}$

$p = \frac{4}{6}$

$p = 0.67$

(b) Ways to select 5 samples (without replacement)

This is calculated using:

$^nC_r = \frac{n!}{(n - r)!r!}$

Where

$r = 5$

So, we have:

$^6C_5 = \frac{6!}{(6 - 5)!5!}$

$^6C_5 = \frac{6!}{1!5!}$

$^6C_5 = \frac{6 \times 5!}{1 \times 5!}$

$^6C_5 = \frac{6}{1}$

$^6C_5 = 6$

Hence, there are 6 ways

(c) All possible sample space of 4

First, we calculate the number of ways to select 4.

This is calculated using:

$^nC_r = \frac{n!}{(n - r)!r!}$

Where

$r = 4$

So, we have:

$^6C_4 = \frac{6!}{(6 - 4)!4!}$

$^6C_4 = \frac{6!}{2!4!}$

$^6C_4 = \frac{6 \times 5 \times 4}{2 \times 1 \times 4!}$

$^6C_4 = \frac{30}{2}$

$^6C_4 = 15$

So, the table is as follows:

$\left[\begin{array}{ccc}TV&Good&Proportion\\1,2,3,4&2&0.5&2,3,4,5&2&0.5&3,4,5,6&2&0.5\\4,5,6,1&3&0.75&5,6,1,2&4&1&6,1,2,3&3&0.75\\1,2,3,5&3&0.75&3,5,6,2&3&0.75&1,3,4,5&2&0.5\\1,3,4,6&2&0.5&1,4,5,2&3&0.75&2,4,6,1&3&0.75\\2,4,6,3&2&0.5&2,4,6,5&3&0.75&3,5,6,1&3&0.75\end{array}\right]$

The proportion column is calculated by dividing the number of Good TVs by the total selected (4) i.e.

$p = \frac{Good}{n}$

(d) The sampling distribution

In (a), we have:

$p = 0.67$ --- proportion of Good TV

The sampling error is calculated as follows:

$SE_n = |p - p_n|$

So, we have:

$\left[\begin{array}{ccc}TV&Good&SE\\1,2,3,4&2&0.17&2,3,4,5&2&0.17&3,4,5,6&2&0.17\\4,5,6,1&3&0.08&5,6,1,2&4&0.33&6,1,2,3&3&0.08\\1,2,3,5&3&0.08&3,5,6,2&3&0.08&1,3,4,5&2&0.17\\1,3,4,6&2&0.17&1,4,5,2&3&0.08&2,4,6,1&3&0.08\\2,4,6,3&2&0.17&2,4,6,5&3&0.08&3,5,6,1&3&0.08\end{array}\right]$

Read more about sampling distributions at:

brainly.com/question/10554762

3 0

3 years ago

PLEASE HELP

Nutka1998 [239]

Answer:

the answer to this is brief outrage

5 0

2 years ago