you eat one slice of a pizza that is cut into 8 even slices. What is the amount you ate written as a decimal

2 answers:

4 0

In order to change a fraction into a decimal you must divide the numerator by the decimal so divide 1 by 8 and so as you go through the equation you get a decimal number because 8 cannot go into 1 of course.

Answer: 0.125 is the amount you ate in decimal form

Bad White [126]3 years ago

3 0

The answer is 0.125
Hope this Helps!

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1.8c+32 c=50 1.8(50)+32

anygoal [31]

Answer:

122

Step-by-step explanation:

1.8 times 50 is 90, and 90 plus 32 is 122

8 0

3 years ago

Read 2 more answers

a teacher and 10 students are to be seated along a bench in the bleachers at a basketball game. In how many ways can this be don

Veronika [31]

Wow !

OK. The line-up on the bench has two "zones" ...

-- One zone, consisting of exactly two people, the teacher and the difficult student.
   Their identities don't change, and their arrangement doesn't change.

-- The other zone, consisting of the other 9 students.
   They can line up in any possible way.

How many ways can you line up 9 students ?

The first one can be any one of 9.   For each of these . . .
The second one can be any one of the remaining 8. For each of these . . .
The third one can be any one of the remaining 7. For each of these . . .
The fourth one can be any one of the remaining 6. For each of these . . .
The fifth one can be any one of the remaining 5. For each of these . . .
The sixth one can be any one of the remaining 4. For each of these . . .
The seventh one can be any one of the remaining 3. For each of these . . .
The eighth one can be either of the remaining 2. For each of these . . .
The ninth one must be the only one remaining student.

   The total number of possible line-ups is

   (9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1) = 9! = 362,880 .

But wait ! We're not done yet !

For each possible line-up, the teacher and the difficult student can sit

-- On the left end,
-- Between the 1st and 2nd students in the lineup,
-- Between the 2nd and 3rd students in the lineup,
-- Between the 3rd and 4th students in the lineup,
-- Between the 4th and 5th students in the lineup,
-- Between the 5th and 6th students in the lineup,
-- Between the 6th and 7th students in the lineup,
-- Between the 7th and 8th students in the lineup,
-- Between the 8th and 9th students in the lineup,
-- On the right end.

That's 10 different places to put the teacher and the difficult student,
in EACH possible line-up of the other 9 .

So the total total number of ways to do this is

   (362,880) x (10) = 3,628,800 ways.

If they sit a different way at every game, the class can see a bunch of games
without duplicating their seating arrangement !

4 0

3 years ago

PLEASE HELP!!! WILL GIVE FIRST ANSWER BRAINLEST!!!!18 is 1.2% of what number

IRINA_888 [86]

So the right answer is 1500.

look at the attached picture⤴

Hope it will help you..