What is the equation for this graph’s lone of best fit. this is due today pls help
1 answer:
Answer:
I don't know if your question is multiple choice or not but here's a close estimate to what it should be.
y =
Step-by-step explanation:
Obviously at a drop of 0 height there would be 0 rebound height so your y-intercept has to be 0.
As for the slope of the line I used the point at 2.5 and 3.
Here are the coordinates (2.5, 1.25) and (3, 1.625)
Find the average rate of change as you see below
1.625 - 1.25 = .375
3 - 2.5 = .5
.375 / .5 = .75 or 3x/4
The points aren't exactly on the line and the graph isn't 100% linear so obviously the equation is not 100% precise. The slope should very close to 0.75 or 3/4.
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Answer:
20 meters
Step-by-step explanation:
The track is circular so it means that after Patrick raced the entire track he is back at the starting point. In other words, every 440 meters he is back to the beginning.
So we would have that, if he races round the track twice, he would run 440(2) = 880 meters and he would be back at the starting point.
The problem asks us how far is he from the starting point at the 900 meter mark. If at 880 meters he is at the starting point, then at 900 meters he would be meters from the starting point.
Answer:
Option A.
Step-by-step explanation:
From the figure attached,
Given : ΔABC ~ ΔDEC
By the property of similarity,
"Corresponding sides of the similar triangles are proportional"
Since,
6x = 42(32 - x)
6x = 1344 - 42x
6x + 42x = 1344
48x = 1344
x =
x = 28 units
Therefore, Option (A). x = 28 units will be the answer.