What is the equation for this graph’s lone of best fit. this is due today pls help
1 answer:
Answer:
I don't know if your question is multiple choice or not but here's a close estimate to what it should be.
y =
Step-by-step explanation:
Obviously at a drop of 0 height there would be 0 rebound height so your y-intercept has to be 0.
As for the slope of the line I used the point at 2.5 and 3.
Here are the coordinates (2.5, 1.25) and (3, 1.625)
Find the average rate of change as you see below
1.625 - 1.25 = .375
3 - 2.5 = .5
.375 / .5 = .75 or 3x/4
The points aren't exactly on the line and the graph isn't 100% linear so obviously the equation is not 100% precise. The slope should very close to 0.75 or 3/4.
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<u>EXPLANATION</u><u>:</u>
Given that
sin θ = 1/2
We know that
sin 3θ = 3 sin θ - 4 sin³ θ
⇛sin 3θ = 3(1/2)-4(1/2)³
⇛sin 3θ = (3/2)-4(1/8)
⇛sin 3θ = (3/2)-(4/8)
⇛sin 3θ = (3/2)-(1/2)
⇛sin 3θ = (3-1)/2
⇛sin 3θ = 2/2
⇛sin 3θ = 1
and
cos 2θ = cos² θ - sin² θ
⇛cos 2θ = 1 - sin² θ - sin² θ
⇛cos 2θ = 1 - 2 sin² θ
Now,
cos 2θ = 1-2(1/2)²
⇛cos 2θ = 1-2(1/4)
⇛cos 2θ = 1-(2/4)
⇛cos 2θ = 1-(1/2)
⇛cos 2θ = (2-1)/2
⇛cos 2θ = 1/2
Now,
The value of sin 3θ /(1+cos 2θ
⇛1/{1+(1/2)}
⇛1/{(2+1)/2}
⇛1/(3/2)
⇛1×(2/3)
⇛(1×2)/3
⇛2/3
<u>Answer</u> : Hence, the req value of sin 3θ /(1+cos 2θ) is 2/3.
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