Answer:

Step-by-step explanation:
Using FOIL (First, outer, inner, last)
First, we multiply 3x and x to get
(First)
We then multiply 3x and 1 to get
(outer)
Then 4 and x to get
(Inner)
Then multiply 1 and 4 to get
(last)
Since the quadratics are all positive, we add all the terms together to get:
. Since 3x and 4x are like terms, we add them together and simplify to get:

And since we can't simplify any further, that's our answer!
Hope this helps :D
The right answer for the question that is being asked and shown above is that:
x = k (1/y)
k = xy
x1y1 = x2y2
8*10 = 6y2
80 = 6y2
y2 = 40/3
So the answer is 40/3
<span>X varies inversely with y and x = 8 when y = 10, what is the value of y when x=6</span>
Answer:
<u>A. (7x)³ + 8 ⇔ 8 added to the product of 7 and x cubed</u>
<u>B. 7x³ + 8 ⇔ 8 added to cube of 7x</u>
<u>C. 7 (x + 8)³ ⇔ 7 times the cube of the sum of x and 8</u>
<u>D. (7x + 8)³ ⇔ the cube of the sum of 7x and 8</u>
Step-by-step explanation:
1. Let's drag the tiles to the correct boxes to complete the pairs.
A. (7x)³ + 8 ⇔ 8 added to the product of 7 and x cubed
The second tile was already given and solved, however we're copying it.
B. 7x³ + 8 ⇔ 8 added to cube of 7x
C. 7 (x + 8)³ ⇔ 7 times the cube of the sum of x and 8
We use the expression 7 times because number 7 is multiplying the sum inside the parenthesis.
D. (7x + 8)³ ⇔ the cube of the sum of 7x and 8
12,000÷10,000=1.2
1.2×50=60
Answer:
425.25
Step-by-step explanation:
Since we are given 36th term as 14 and we know common difference is
, it means that from the first term, we add
to each and get 14 on the 36th term. To figure out the first term, thus, we have to subtract
35 times from 14. Let's do it to get first term:

The sum of arithmetic sequence formula is:
![S_{n}=\frac{n}{2}[2a+(n-1)d]](https://tex.z-dn.net/?f=S_%7Bn%7D%3D%5Cfrac%7Bn%7D%7B2%7D%5B2a%2B%28n-1%29d%5D)
Where,
is the sum of nth term (we want to figure this out for first 36 terms)
is the first term (we figured this out to be 9.625)
is the term number (36 for our case)
is the common difference (given as
)
Substituting all the values, we get:
![S_{36}=\frac{36}{2}[2(9.625)+(36-1)(\frac{1}{8})]\\S_{36}=18[19.25+4.375]\\S_{36}=18[23.625]\\S_{36}=425.25](https://tex.z-dn.net/?f=S_%7B36%7D%3D%5Cfrac%7B36%7D%7B2%7D%5B2%289.625%29%2B%2836-1%29%28%5Cfrac%7B1%7D%7B8%7D%29%5D%5C%5CS_%7B36%7D%3D18%5B19.25%2B4.375%5D%5C%5CS_%7B36%7D%3D18%5B23.625%5D%5C%5CS_%7B36%7D%3D425.25)
First answer choice is right.