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Margarita [4]
3 years ago
13

last week a candle store recieved 335.60 for selling 20 candles. small candles sell for 10.98 and largr candles sell fer 27.98.

how many large canfles did the store sell
Mathematics
1 answer:
mina [271]3 years ago
5 0
Hmmmm closest I can get to this answer is 6 or 7. The numbers don't add up and it's probably why you haven't received an answer. If you do this math:
13small candles multiplied by 10.98 = 142.74
7large candles multiplied by 27.98 = 195.86
142.74+195.86 = 338.60 which is OVER the total received.
7+13=20 candles
14small candles multiplied by 10.98 = 153.72
6 large candles multiplied by 27.98 = 167.88
153.72+167.88 = 321.60 which is UNDER the total received
Can't go any lower or higher because it's even lower or higher. 
6+14=20 candles
So I wouldn't really know what to say. This isn't adding up.

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< B.5 14. Multiply & simplify: (3x + 4)(x + 1)​
kondor19780726 [428]

Answer:

3x^2+7x+4

Step-by-step explanation:

Using FOIL (First, outer, inner, last)

First, we multiply 3x and x to get 3x^2 (First)

We then multiply 3x and 1 to get 3x (outer)

Then 4 and x to get 4x (Inner)

Then multiply 1 and 4 to get 4 (last)

Since the quadratics are all positive, we add all the terms together to get:

3x^2+3x+4x+4. Since 3x and 4x are like terms, we add them together and simplify to get:

3x^2+7x+4

And since we can't simplify any further, that's our answer!

Hope this helps :D

6 0
3 years ago
Read 2 more answers
X varies inversely with y and x = 8 when y = 10, what is the value of y when x=6
Alja [10]
The right answer for the question that is being asked and shown above is that:

x = k (1/y)
k = xy

x1y1 = x2y2
8*10 = 6y2
80 = 6y2
y2 = 40/3

So the answer is 40/3
<span>X varies inversely with y and x = 8 when y = 10, what is the value of y when x=6</span>
3 0
3 years ago
Drag the tiles to the correct boxes to complete the pairs. Match each expression to the correct verbal description. 8 added to t
QveST [7]

Answer:

<u>A. (7x)³ + 8 ⇔ 8 added to the product of 7 and x cubed</u>

<u>B. 7x³ + 8 ⇔ 8 added to cube of 7x</u>

<u>C. 7 (x + 8)³ ⇔ 7 times the cube of the sum of x and 8</u>

<u>D.  (7x + 8)³ ⇔ the cube of the sum of 7x and 8</u>

Step-by-step explanation:

1. Let's drag the tiles to the correct boxes to complete the pairs.

A. (7x)³ + 8 ⇔ 8 added to the product of 7 and x cubed

The second tile was already given and solved, however we're copying it.

B. 7x³ + 8 ⇔ 8 added to cube of 7x

C. 7 (x + 8)³ ⇔ 7 times the cube of the sum of x and 8

We use the expression 7 times because number 7 is multiplying the sum inside the parenthesis.

D.  (7x + 8)³ ⇔ the cube of the sum of 7x and 8

6 0
3 years ago
Chuck's Computer Corporation has 10,000 shares of stock outstanding.
Svetllana [295]
12,000÷10,000=1.2
1.2×50=60
8 0
3 years ago
Read 2 more answers
Calculate the sum of the first 36 terms of the arithmetic sequence defined in which a36=14 and the common difference is d=1/8
user100 [1]

Answer:

425.25


Step-by-step explanation:

Since we are given 36th term as 14 and we know common difference is \frac{1}{8}, it means that from the first term, we add \frac{1}{8} to each and get 14 on the 36th term. To figure out the first term, thus, we have to subtract \frac{1}{8} 35 times from 14. Let's do it to get first term:

14-35(\frac{1}{8})=\frac{77}{8}=9.625

The sum of arithmetic sequence formula is:

S_{n}=\frac{n}{2}[2a+(n-1)d]

Where,

  • S_{n} is the sum of nth term (we want to figure this out for first 36 terms)
  • a is the first term (we figured this out to be 9.625)
  • n is the term number (36 for our case)
  • d is the common difference (given as \frac{1}{8})

Substituting all the values, we get:

S_{36}=\frac{36}{2}[2(9.625)+(36-1)(\frac{1}{8})]\\S_{36}=18[19.25+4.375]\\S_{36}=18[23.625]\\S_{36}=425.25

First answer choice is right.


7 0
3 years ago
Read 2 more answers
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