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ad-work [718]
3 years ago
7

Solve the system using substitution: y + 8x = 10 and 2y - 4x = 40

Mathematics
1 answer:
exis [7]3 years ago
4 0

Answer:

Hence x = -1 and y = 18

<em></em>

Step-by-step explanation:

Given the system of equations

y + 8x = 10... 1

2y - 4x = 40 ... 2

From 1; y = 10-8x

Substitute into 2;

2(10-8x) - 4x = 40

20 - 16x - 4x = 40

20 - 20x = 40

-20x = 40 - 20

-20x = 20

x = -1

Recall that y = 10-8x

y = 10 - 8(-1)

y = 10 + 8

y = 18

Hence x = -1 and y = 18

<em></em>

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2 years ago
Security A rounds every 2 minutes and 20 seconds in the gate 1. Security B rounds every 1 minute and 40 seconds in the gate 2. I
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Answer:

Time = 11\frac{2}{3}\ min

Step-by-step explanation:

Given

Security\ A = 2\ mins, 20\ secs

Security\ B = 1\ mins, 40\ secs

Required

After how many minutes, will they round together

First, convert the given time to minutes

Security\ A = 2\ mins, 20\ secs

Security\ A = 2\ mins+ 20\ secs

Security\ A = 2\ mins+ \frac{20}{60}\ min

Security\ A = 2\ mins+ \frac{1}{3}\ min

Security\ A = 2\frac{1}{3}\ min

Security\ B = 1\ mins, 40\ secs

Security\ B = 1\ mins+ 40\ secs

Security\ B = 1\ mins+ \frac{40}{60}\ min

Security\ B = 1\frac{2}{3}\ min

So, we have:

Security\ A = 2\frac{1}{3}\ min

Security\ B = 1\frac{2}{3}\ min

List out the multiples of the time of both security personnel take round.

Security\ A = 2\frac{1}{3}min,\ 4\frac{2}{3}min,\ 7min,\ 9\frac{1}{3}min,\ 11\frac{2}{3}min...

Security\ B = 1\frac{2}{3}min,\ 3\frac{1}{3}min,\ 5min,\ 6\frac{2}{3}min,\ 8\frac{1}{3}min,\ 10min\ ,11\frac{2}{3}min,...

In the above lists, the common time is:

Time = 11\frac{2}{3}\ min

<em>This implies that they go on round after </em>11\frac{2}{3}\ min<em></em>

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3 years ago
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Answer:

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icang [17]

Answer:

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Step-by-step explanation:

Using the rule of radicals

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