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Neko [114]
3 years ago
5

8 and 21 to 40 as a decimal

Mathematics
2 answers:
Thepotemich [5.8K]3 years ago
8 0
.08
.21
.40
is the right answer
kari74 [83]3 years ago
6 0
.08, .21, and .40 are the decimals for those numbers!!
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Can someone help me in this plssss I really need it
kompoz [17]

Answer:

\boxed{-3xy^{2}\sqrt [3] {2x^{2}}}

Step-by-step explanation:

Your expression is

\sqrt [3] {-54x^{5}y^{6}}

Here's how I would simplify it.

\begin{array}{rcll}\sqrt [3] {-54x^{5}y^{6}} & = & \sqrt [3] {(-1)^{3}\times 2 \times 27 \times x^{2} \times x^{3} \times y^{6}} & \text{Factored the cubes}\\& = & \sqrt [3] {(-1)^{3} \times 3^{3}\times x^{3} \times y^{6}\times 2 \times x^{2}} & \text{Grouped the cubes}\\\end{array}

\begin{array}{rcll}& = & \sqrt [3] {(-1)^{3} \times {3^{3}\times x^{3} \times y^{6}}} \times\sqrt [3] { 2 \times x^{2}} & \text{Separated the cubes}\\&=& \mathbf{-3xy^{2}\sqrt [3] {2x^{2}}} & \text{Took cube roots}\\\end{array}

\text{The simplified expression is $\boxed{\mathbf{-3xy^{2}\sqrt [3] {2x^{2}}}}$}

6 0
4 years ago
If the area of a rectangle is 64cm squared, how many different perimeters are possible when the dimensions are whole numbers
FinnZ [79.3K]

Answer:

2 different perimeters, 32 cm and 40 cm

Step-by-step explanation:

Given the area of a rectangle is 64 cm squared.

We know, Area of the rectangle is = length x breath

∴  64 = 8 x 8

Hence the sides can be 8 cm by 8 cm.

So the perimeter of the rectangle is = 8 cm + 8 cm + 8 cm +8 cm

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Also, Area of the rectangle is = length x breath

∴  64 = 16 x 4

So the perimeter of the rectangle is = 16 cm + 4 cm + 16 cm +4 cm

                                                            = 40 cm  

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84, 99, 88, 82, 95, 85
Vladimir [108]

Answer:

97

Step-by-step explanation:

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Which shows the use of the associative property?
aivan3 [116]

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B shows the associative property

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