Question

The equation of line QR is x + 2y = 2. What is the equation of a line perpendicular to line QR in slope-intercept form that contains point (5, 6)?
A) y = negative one halfx + seventeen halves
B) y = 2x − 4
C) y = negative one halfx + seven halves
D) y = 2x + 16

Answer 1

Answer:

y = 2x-4

Step-by-step explanation:

x + 2y = 2

The slope intercept form is

y = mx+b where m is the slope and b is the y intercept

First find the slope of the line

2y = -x+2

Divide by 2

y = -1/2x +1

The slope of this line is -1/2

We want a line that is perpendicular, which is the negative reciprocal

-1 /(-1/2) = 2

The slope intercept form is

y = mx+b where m is the slope and b is the y intercept

y = 2x+b

Substitute the point into the line

6 = 2(5)+b

6 = 10+b

6-10 =b

-4=b

y = 2x-4