We can compare the two units or object performances by that.... even in the case of magnitude lower than zero....
Ok so first following the order of opperation (P.E.M.D.A.S.)
We have to multiply first so 1/4*4/9 is 4/36
2/3-4/36
We have to get them both to have the same denominator
What times 3 is 36? 12
So multiply 2*12 and 3*12 you get
24/36-4/36=5/9(simplified)
Answer:
B, D
Step-by-step explanation:
Sorry if I'm wrong. I dont know if E is right or not
Answer:
91.02% probability of selling more than 4 properties in one week.
Step-by-step explanation:
For each property, there are only two possible outcomes. Either it is sold, or it is not. The chance of selling any one property is independent of selling another property. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which
is the number of different combinations of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.
In this problem we have that:

Compute the probability of selling more than 4 properties in one week.
Either you sell 4 or less properties in one week, or you sell more. The sum of the probabilities of these events is decimal 1. So

We want to find
. So

In which

So






So

Finally

91.02% probability of selling more than 4 properties in one week.