I believe the answers are A. C. D.
Since it's been crossed with a homozygous wrinkled green, the offspring has a genotype for heterozygous round and yellow. As round and yellow are dominant traits, they're expressed in the phenotype. But when self pollinated in the f2 generation, the recessive ones will show as well
Hope it helps :')
Correct question:
if a nondisjunction occurs at anaphase I of the first meiotic division, what will the proportion of abnormal gametes (for the chromosomes involved in the nondisjunction)?
Answer:
100%
Explanation:
Nondisjunction at meiosis-I means that two homologous chromosomes of at least one homologous pair fail to separate from each other during anaphase-I. This would result in the formation of one cell with one extra chromosome and the other with one less chromosome by the end of meiosis-I. Meiosis-II in these two cells would maintain this chromosome number in the daughter cells. Therefore, out of the total four gametes formed by the end of the meiosis, two would have one extra chromosome and would be denoted as "n+1". The rest of the two gametes would have one less chromosome and would be denoted as "n-1".
Answer:
Selection that acts, over evolutionary time, to enhance traits that increase an individual's ability to mate frequently or with quality partners is known as <u>sexual selection.</u>
Explanation:
Sexual selection : The process through which males and females attempt to maximise their chances of reproductive success is called sexual selection. It is a form of natural selection. Charles Darwin suggested sexual selection. Animals compete with others of the same species for the chance to mate.
<u>For example:</u> Male widow-bird grows exceptional long tail feathers, females lack tail feathers.
