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dmitriy555 [2]
3 years ago
13

Solve the following 3x^2 -2x +5 greater than and equals to 0

Mathematics
1 answer:
Leviafan [203]3 years ago
3 0

Answer:

3x^2-2x+5>or=0

9x-2x+5>or=0

7x>or=-5

x>or=0.8

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7 0
3 years ago
7 calculators cost £81.90.<br> How much do 11 calculators cost?
Leno4ka [110]

Answer:

128.7

Step-by-step explanation:

81.90 ÷ 7  = 11.7

11.7 x 11 = 128.7

3 0
3 years ago
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Each Sunday during his nine week summer vacation, Ray buys a newspaper. The Sunday paper costs $1.85. ABOUT how much does Ray sp
anygoal [31]
1.85×9 is your answer - I'm not American drk about dollars
6 0
3 years ago
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Write out the five number summary for each data set.
Zanzabum

I'll do problem 1 to get you started

First sort the values from smallest to largest and you should end up with this set

{1, 6, 7, 11, 13, 16, 18, 21, 22, 23}

The smallest value is 1 and the largest value is 23, so the min and max are 1 and 23 in that order.

We have ten values in this set. The middle-most number is going to be between the 10/2 = 5th slot and the 6th slot. The numbers 13 and 16 are in the fifth and sixth slots respectively. Average those values to get (13+16)/2 = 29/2 = 14.5

The median is 14.5 which is another name for the second quartile (Q2).

Now split the data set into two halves

L = lower half of values smaller than the median

U = upper half of values larger than the median

In this case,

L = {1, 6, 7, 11, 13}

U = {16, 18, 21, 22, 23}

sets L and U have five items each

Find the median of set L and U to get 7 and 21 respectively. These medians of L and U represent the values of Q1 and Q3 in that order.

Q1 = first quartile = 7

Q3 = third quartile = 21

===================================================

Answer:

The five number summary for problem 1 is

  • Minimum = 1
  • Q1 = 7
  • Q2 = 14.5  (this is the median)
  • Q3 = 21
  • Maximum = 23
5 0
3 years ago
Solve the equation below 3c=15
rewona [7]

Hey there!☺

Answer:\boxed{c=5}

Explanation:

3c=15

3c/3 = 15/3 Divide both sides by 3

15/3 = 5 Simplify 15/3

c = 5

Hope this helps!

4 0
3 years ago
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