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Rainbow [258]
2 years ago
10

Find the distance between the points (−5,2) and (9.2)​

Mathematics
1 answer:
forsale [732]2 years ago
4 0

Step-by-step explanation:

<u>Formula</u><u> </u><u>U</u><u>s</u><u>e</u><u>d</u>

<u>By distance formula,</u>

  • d (A,B)=√[(x₁ - x₂)² + (y₁ - y₂)²]

\sf \longmapsto \: D = √(x2-x1)²+(y2-y1)²

\sf \longmapsto= √(9+5)²+(2-2)²

\sf \longmapsto= = √14²+09

\sf \red \longmapsto \boxed{= 14}

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10 times as many as _ hundreds is 60 hundreds or _ thousands
Lady_Fox [76]

60 hundreds means 6000 = 6 thousands;

So, 10 · x = 6000;

x = 600;

600 means 6 hundreds;

Finally, 10 times as many as 6 hundreds is 60 hundreds or 6 thousands.

6 0
3 years ago
2x^3y + 18xy - 10x^2y - 90y Part A: Rewrite the expression so that the GCF is factored completely.
KATRIN_1 [288]
2(x^3y+9xy-5x^2y-45y)
4 0
3 years ago
PLEASE HELP ME THIS.. I REALLY NEED<br> HELP
Colt1911 [192]

9514 1404 393

Answer:

  5 hours

Step-by-step explanation:

A quick way to look at this is to compare the difference in hourly charge to the difference in 0-hour charge.

The first day, the charge is $3 more than $12 per hour.

The second day, the charge is $12 less than $15 per hour.

The difference in 0-hour charges is 3 -(-12) = 15. The difference in per-hour charges is 15 -12 = 3. The ratio of these is ...

  $15/($3/h) = 5 h

The charges are the same after 5 hours.

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If you write equations for the charges, they will look like ...

  y1 = 15 + 12(x -1)

  y2 = 3 + 15(x -1)

Equating these charges, we have ...

  15 +12(x -1) = 3 + 15(x -1)

  12x +3 = 15x -12 . . . . . . . . eliminate parentheses

  15 = 3x . . . . . . . . . . add 12-12x

  x = 15/3 = 5 . . . . . . divide by 3

You might notice that the math here is very similar to that described in words, above.

The charges are the same after 5 hours.

6 0
2 years ago
Help me please I'm not sure
Ahat [919]
Help you with what? Be specific. <span />
8 0
3 years ago
Read 2 more answers
Divide and answer in simplest form: 1 2 ÷ 4 A) 1 8 B) 2 1 C) 4 2 D) 8 1
denis23 [38]
\dfrac{1}{2}  \div 4 =  \dfrac{1}{2}  \times \dfrac{1}{4}  = \dfrac{1}{8}


Answer: 1/8 (Answer A)
4 0
3 years ago
Read 2 more answers
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