What is the distance between the points (4 3) and (1 -1) on the cordinate plane

Mathematics

2 answers:

katen-ka-za [31]2 years ago

8 0

Answer:

d = 5

Step-by-step explanation:

Distance formula: $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

d = sqrt[(1-4)^2+(-1-3)^2]

d = 5

Amanda [17]2 years ago

4 0

Answer:

Step-by-step explanation:

distance = square root of (1-4)^2 + (-1-3)^2

=> distance = square root of -3^2 + (-4)^2

=> distance = square root of 9 + 16

=> distance = square root of 25

=> distance = 5

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