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Gwar [14]
2 years ago
9

Find the distance between the points given. (0, 6) and (5, 12)

Mathematics
1 answer:
MA_775_DIABLO [31]2 years ago
4 0

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Please help me answer this question
I am Lyosha [343]

9514 1404 393

Answer:

  D.  -17%

Step-by-step explanation:

The change from March to April is (April - March) = (100 -120) = -20. As a fraction of the March bill, that is ...

  -20/120 = -1/6

As a percentage, that change is ...

  -1/6 × 100% ≈ -16.667% ≈ -17%

The electric bill changed by about -17% from March to April.

_____

<em>Additional comment</em>

Water went up 4%; groceries went up about 14%, and restaurant changed by -15%.

The percentage change is found by ...

  % change = ((new amount)/(original amount) -1) × 100%

Above, we have rearranged this to ...

  % change = ((new amount) -(original amount))/(original amount) × 100%

8 0
2 years ago
Which of the following would be the best method for investigating the correlation between the hibernation habits of bears and th
Andre45 [30]

Answer: Observational study

Step-by-step explanation: I just took the test

4 0
2 years ago
Write a numerical expression for the verbal expression. the difference of six and two divided by four
Ilia_Sergeevich [38]

Answer:

(6-2)/4

Step-by-step explanation:

Make sure you have the parenthesis

6 0
3 years ago
A. 13 π<br> B. 6.5 π<br> C. 42.25 π<br> D. 60 π
AleksandrR [38]

Answer:

  • 12^2 + 5^2= c^2
  • c=13
  • Area of circle
  • A= pi× r^2
  • <em>A</em><em>=</em><em> </em><em>42.25</em><em>×</em><em>pi</em>
  • C
  • I do exams and quizzes if your interested, guaranteed A!
3 0
3 years ago
A vase has the shape of a rectangular prism. The inside of the vase is also a rectangular prism. What is the volume of the solid
saw5 [17]

Answer:

V_{s} = \frac{\pi}{4}\cdot D_{out}^{2} \cdot h -\frac{\pi}{4}\cdot (D_{out}-2\cdot t)^{2}\cdot (h-t)

Step-by-step explanation:

The geometric description of the vase is described in the image attached below. The volume of the solid part of the vase is:

V_{s} = V_{out} - V_{in}

V_{s} = \frac{\pi}{4}\cdot D_{out}^{2} \cdot h -\frac{\pi}{4}\cdot (D_{out}-2\cdot t)^{2}\cdot (h-t)

Where:

D_{out} - Outer diameter, in centimeters.

t - Vase thickness, in centimeters.

3 0
3 years ago
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