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Gwar [14]
3 years ago
9

Find the distance between the points given. (0, 6) and (5, 12)

Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
4 0

62hshhsjshsjsjsjsjjsjsjs

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67 1/2 * (-1/3) it is due on Wednesday and for some reason I cont figure out this one
krok68 [10]

Answer:

-45/2

Step-by-step explanation:

67 1/2 * (-1/3)

67 1/2 = 135/2

So 135/2*1/3=45/2

45/2*-1=-45/2

7 0
1 year ago
What's 400 divided by 5 show your work
vlada-n [284]
5 goes into 40 8 times than add a zero
6 0
3 years ago
Line b passes through points (5, 5) and (10, 8). Line c passes through points (4, 8) and (1, 13). Are line b and line c parallel
lora16 [44]

Answer:

Step-by-step explanation:

In going from (5, 5) to (10, 8), x (the run) increases by 5 and y (the rise) increases by 3.  Thus, the slope of the line connecting the first two points is m = 3/5.

In going from (1, 13) to (4, 8), x (the run) increases by 3 and y (the rise) decreases by 5.  Thus, the slope of the line connecting the first two points is m = -5/3

Because these results are negative reciprocals of one another, the two lines are PERPENDICULAR to one another.

3 0
4 years ago
Media experts claim that daily print newspapers are declining because of Internet access. Listed​ below, from left to right and
yKpoI14uk [10]

Answer:

(a) The median is 1478

(b) Null hypothesis H₀ : μ₁ = μ₂

Alternative hypothesis Hₐ : μ₁ > μ₂

(c) The test statistic  t_{\alpha/2} is 6.678155

(d) The p value is  1.2×10⁻¹¹

(e) We reject our null hypothesis H₀. In terms of the test, there is sufficient evidence to suggest that there is a trend in the numbers of daily newspaper because the probability for a decrease in the numbers is very high

Step-by-step explanation:

(a) Here we have the data as follows;

1623 1586 1574 1554 1544 1531 1519 1513 1491 1484 1478 1471 1458 1456 1458 1453 1438 1428 1405 1395 1377

The median is = 1478

Therefore we have above the median  

1623 1586 1574 1554 1544 1531 1519 1513 1491 1484

The mean,  \bar{x}_{1}= 1541.9

Standard deviation, σ₁ = 41.38224257

n₁ = 10

Below the median  

1471 1458 1456 1458 1453 1438 1428 1405 1395 1377

The mean,  \bar{x}_{2}}= 1433.9

Standard deviation, σ₂ = 30.04812806

n₂ = 10

(b) Null hypothesis H₀ : μ₁ = μ₂

Alternative hypothesis Hₐ : μ₁ > μ₂

(c) The formula for t test is given by;

t_{\alpha/2} =\frac{(\bar{x}_{1}-\bar{x}_{2})}{\sqrt{\frac{\sigma_{1}^{2} }{n_{1}}-\frac{\sigma _{2}^{2}}{n_{2}}}}

df = 10 - 1 = 9, α = 0.05

Therefore, the test statistic  t_{\alpha/2} = 6.678155

(d) The p value from statistical relations is Probability p = 1.2×10⁻¹¹

Critical z at 5% confidence level = 1.645

Since P << 0.05, e reject the

(e) Therefore, we reject our null hypothesis H₀. In terms of the test, there is sufficient evidence to suggest that there is a trend in the numbers of daily newspaper because the probability for a decrease in the numbers is very high.

5 0
3 years ago
I dont get the whole line graphing solution thing please help me out
SVEN [57.7K]
(3,-2) it’s where the both lines meet
7 0
3 years ago
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