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3 years ago

Subtraction with renaming estimate 2 1/6- 1 2/7

Mathematics

1 answer:

Snezhnost [94]3 years ago

3 0

13/6-9/7
Find the Least Common Denominator (LCD)
In this case, 42.
(7/7)(13/6)-(6/6)(9/7)
37/42 is your answer

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An artist builds a sculpture out of metal and wood that weighs 14.9 kilograms. 3/4 of this weight is metal and the rest is wood.

Troyanec [42]

Answer:

Given is a sculpture that is built up of metal and wood, and the weight of this sculpture is 14.9 kilograms.

It says that three-fourth of the total weight is metal and says to find the weight of wooden part.

We can find the weight of metal part and then subtract it from the total weight to calculate the answer.

Total weight = 14.9 kilograms.

Metal part = three-fourth of total weight =

Wooden part = 14.9 - 11.175 = 3.725 kilograms.

Hence, the wooden part is 3.725 kilograms.

Step-by-step explanation:

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2 years ago

Which set of shapes contains members that are always similar to one another?.

Viefleur [7K]

Answer: Equilateral triangles.

Explanation: We know that in similar polygons, its all the corresponding angles are congruent. Only the set of equilateral triangles contains members that are always similar( by AAA similarity criteria) to one another as the measure of all the angles of equilateral triangle is fixed i.e. 60°.
Rest other do not have fixed measure for angles in it.

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2 years ago

The radii of two circles are in the ratio of 3 to 1. Find the area of the smaller circle if the area of the larger circle is 27

Naddik [55]

ANSWER
$3\pi sq.\: in.$

EXPLANATION

Let R be the radius of the bigger circle and r, be the radius of the smaller circle.

Then their ratio is given as,

$R:r=3:1$

We can rewrite it as fractions to get,

$\frac{R}{r} = \frac{3}{1}$

We make R the subject to get,

$R = 3r$

The area of the bigger circle can be found using the formula,

$Area=\pi {r}^{2}$

This implies that,

$Area=\pi ({3r})^{2}$

$Area=9\pi {r}^{2}$

But it was given in the question that, the area of the bigger circle is 27π.

$27\pi=9\pi {r}^{2}$

We divide through by 9π to get,

$3 = {r}^{2}$

This means that,
$r = \sqrt{3}$

The area of the smaller circle is therefore

$= \pi {( \sqrt{3}) }^{2}$

$= 3\pi$

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3 years ago

Read 2 more answers

A method for determining whether a critical point is a minimum. True or false?

natita [175]

Answer:

We can find if a critical point is a local minimum or maximum by looking at the second derivatives.

Step-by-step explanation:

If you take the first derivative, you will find the slope at the given point, which if it is a minimum or a maximum will be 0.

Then we take the second derivative. If that number is a positive number, then we have a local minimum. If it is a negative number, then it is a local maximum.

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3 years ago

Please help, it's urgent!

Aneli [31]

For this case we have to, by defining properties of powers and roots the following is fulfilled:

$\sqrt [n] {a ^ m} = a ^ {\frac {m} {n}}$