How to solve this equation
2 answers:
You might be interested in
Answer:
The statement is false.
Step-by-step explanation:
Here we need to remember some things:
Integer numbers are closed under multiplication.
This means that for two integers a and b, the product a*b is also an integer.
A rational number is a number that can be written as the quotient of two integer numbers.
An irrational number is a number that can't be written as the quotient of two rational numbers.
Now let's see the statement:
"The product of two rational numbers is irrational."
The product of two rational numbers is written as:
Where a, c, b, and d are integers.
We can rewrite that product as:
Because of the first property, we know that a*c is an integer, and b*d is also an integer, so here we have a quotient of two integer numbers, so this is a rational number.
Then the product of two rational numbers is a rational number.
Then the statement is false.
Answer:
Option (d).
Step-by-step explanation:
Note: The base of log is missing in h(x).
Consider the given functions are
The function m(x) can be written as
...(1)
The translation is defined as
.... (2)
Where, a is horizontal shift and b is vertical shift.
If a>0, then the graph shifts a units left and if a<0, then the graph shifts a units right.
If b>0, then the graph shifts b units up and if b<0, then the graph shifts b units down.
On comparing (1) and (2), we get
Therefore, we have to translate each point of the graph of h(x) 3 units left to get the graph of m(x).
Hence, option (d) is correct.