All categories

3 years ago

Solve for x

}^{2} = 7x + 2" alt="4 {x}^{2} = 7x + 2" align="absmiddle" class="latex-formula">

Mathematics

1 answer:

Alina [70]3 years ago

7 0

$\bf 4x^2=7x+2\implies 4x^2-7x-2=0\implies (4x+1)(x-2)=0 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ 4x\cdot x=\boxed{4x^2}~\hfill (1)(-2)=\boxed{-2}\hfill (4x\cdot -2)+(1\cdot x)=\boxed{-7x} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} 4x+1=0\implies 4x=-1\implies &x=-\cfrac{1}{4}\\[1em] x-2=0\implies &x=2 \end{cases}$

You might be interested in

Cole rolls a number cube multiple times and records the data in the table above. At the end of the experiment, he counts that he

Zigmanuir [339]

Experimental Probability is the ratio of the number of times an event occurs to the total number of trials.

Given that Cole rolls a number cube multiple times and records the data in the table below. At the end of the experiment, he counts that he has rolled 190 fours.

From the table, we see that the total number of trials is 1,000 and there are 190 fours.

Therefore, the experimental probability of rolling a four, based on Cole’s experiment is given by 190 / 1,000 = 0.19 = 0.190 to the nearest thousandth.

8 0

3 years ago

Read 2 more answers

The radius of a cylindrical water tank is 5.5ft, and its height is 13ft. What is the volume of the tank?

svetlana [45]

Answer:

The volume of the tank is 1235ft³

Step-by-step explanation:

To calculate the volume of a cylinder we have to use the following formula:

v = volume

h = height = 13ft

π = 3.14

r = radius = 5.5ft

v = (π * r²) * h

we replace the unknowns with the values we know

v = (3.14 * (5.5ft)²) * 13ft

v = (3.14 * 30.25ft²) * 13ft

v = 94.985ft² * 13ft

v = 1234.805ft³

Round to the nearest whole number

v = 1234.805ft³ = v = 1235ft³

4 0

3 years ago

3. QR find the arc length 02.83 021.99 O 12.57 0 34.56

jeka94

Your answer should be 12.57

8 0

3 years ago

What is the relationship between Za and Zb? D А E a 6 С B Choose 1 answer: A Vertical angles ® Complementary angles B C Suppleme

Free_Kalibri [48]

Answer:

D. none of the above.

Step-by-step explanation:

7 0

3 years ago

The functions f (theta) and g (theta) are sine functions, where f (0) equals g (0) equals 0.The amplitude of f (theta) is twice

777dan777 [17]

If period of $f(\theta)$ is one-half the period of $g(\theta)$ and
 $g(\theta)$ has a period of 2π, then $T_{g} =2T_{f}=2 \pi$ and $T_{f}= \pi$ .

To find the period of sine function $f(\theta)=asin(b\theta+c)$ we use the rule $T_{f}= \frac{2\pi}{b}$ .

f is sine function where f (0)=0, then c=0; with period $\pi$ , then $f(\theta)=asin 2\theta$ , because $T_{f}= \frac{2 \pi }{2} = \pi$ .

To find a we consider the condition $f( \frac{ \pi }{4} )=4$ , from where $asin2* \frac{\pi}{4} =a*sin \frac{ \pi }{2} =a=4$ .

If the amplitude of $f(\theta)$ is twice the amplitude of $g(\theta)$ , then $g(\theta)$ has a product factor twice smaller than $f(\theta)$ and while period of $g(\theta)$ is 2π and g(0)=0, we can write $g(\theta)=2sin\theta$ .

8 0

3 years ago