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Ksivusya [100]
3 years ago
13

Anyone help me, please I need help

D%7Bx%20-%202%7D%20" id="TexFormula1" title=" \sqrt{x - 5} = 8 \sqrt[]{x - 2} " alt=" \sqrt{x - 5} = 8 \sqrt[]{x - 2} " align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
Ilya [14]3 years ago
7 0

Answer:

No Real Solutions.

Step-by-step explanation:

√(x-5)=8√(x-2)

Square on both sides,

(√(x-5))^2=(8√(x-2))^2

or,(x-5)=64(x-2)

or,x-5=64x-128

or,-5+128=64x-x

or,123/63=x

Therefore, x=41/21

If you plug x=41/21 in √(x-5)=8√(x-2) you do not get equals, so the problem has no real solutions.

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Answer:

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Step-by-step explanation:

Multiply each term by its counterpart in the parenthesis.

4x*3x and 4x*-7

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This gives you 12x^2-4x*7+3x-7 when the like terms are combined.

Collect the like terms, which will give you 12x^2-25x-7

7 0
3 years ago
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(I could answer more confidently if I had more context to the question)

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Answer:

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3. A quadratic polynomial whose<br>product and the sum of<br>zéroes are -12 and 1​
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Step-by-step explanation:

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