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Taya2010 [7]
3 years ago
9

A biologist is researching a newly-discovered species of bacteria. He puts 1,000 bacteria into what he has determined to be a fa

vorable growth medium. 12 hours later, he measures 12,500 bacteria. Assuming exponential growth, find the growth equation and use it to determine the number of bacteria after 20 hours.
Mathematics
1 answer:
Masteriza [31]3 years ago
8 0
The bacteria grow from 1,000 bacteria into 12,500 bacteria in 12 hours.  The exponent function would be
:an= ao(1+r)^t12.500= 1,000(1+r)^121,000(12.5)= 1,000(1+r)^1212.5= (1+r)^121+r= 1.23427r= 0.23Number of bacteria after 20hr would be:an= ao(1+r)^tan= 1,000(1+0.23)^20an= 1,000(62.821 )an= 62,821
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Answer:

x = 3

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Step-by-step explanation:

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3+y=2

y=2-3

y=-1

Check by subbing x=3 and y=-1 into x-y=4

(3)-(-1) = 3+1 = 4

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In a shelter, the number of kennels is proportional to the number of dogs. The constant of proportionality in terms of dogs per
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There are 9 kennels.

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27 = 3 (# of kennels)

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What does the constant 2.2 in L(D) represent?
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Step-by-step explanation:

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3 years ago
Use the following explicit function to identify f(1) & r, and list the first five terms of the sequence.
rjkz [21]

Given:

The explicit function is:

f(n)=1000\left(\dfrac{1}{4}\right)^{n-1}

To find:

f(1)=?,r=? and first 5 terms.

Solution:

The explicit formula a geometric sequence is:

f(n)=ar^{n-1}            ...(i)

Where, a is the first term and r is the common ratio.

We have,

f(n)=1000\left(\dfrac{1}{4}\right)^{n-1}         ...(ii)

On comparing (i) and (ii), we get

a=1000

f(1)=1000

And,

r=\dfrac{1}{4}

For n=1,

f(1)=1000\left(\dfrac{1}{4}\right)^{1-1}

f(1)=1000\left(\dfrac{1}{4}\right)^{0}

f(1)=1000(1)

f(1)=1000

For n=2,

f(2)=1000\left(\dfrac{1}{4}\right)^{2-1}

f(2)=1000\left(\dfrac{1}{4}\right)^{1}

f(2)=1000\times \dfrac{1}{4}

f(2)=250

Similarly, substituting n=3,4,5, we get

f(3)=62.5

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Therefore, f(1)=1000,r=\dfrac{1}{4} and the first five terms are 1000,250,62.5,15.625,3.90625.

5 0
3 years ago
Read 2 more answers
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