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lbvjy [14]
3 years ago
9

Karl is putting a frame around a rectangular photograph. The photograph is 14 inches long and 10 inches wide, and the frame is t

he same width all the way around. What will be the area of the framed photograph?
Mathematics
1 answer:
Sergeu [11.5K]3 years ago
8 0
<h2>The area of the framed photograph = 1156 inch^{2}</h2>

Step-by-step explanation:

Given,

The length of photograph (l) = 14 inches and

The breadth of photograph (b) = 10 inches

To find, the area of the framed photograph = ?

We know that,

The area of the framed photograph = (l + 2b)(l + 2b)

= (14 + 2 × 10) (14 + 2 × 10) inch^{2}

= (14 + 20) (14 + 20) inch^{2}

= (34) (34) inch^{2}

= 1156 inch^{2}

∴ The area of the framed photograph = 1156 inch^{2}

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Answer:   (-2, 5) and (2, -3)

<u>Step-by-step explanation:</u>

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y = x^2-2x-3\quad \rightarrow \quad a=1,\ b=-2,\ c=-3\\\\\text{axis of symmetry:}\ x = \dfrac{-b}{2a}\ \longrightarrow \ x=\dfrac{-(-2)}{2(1)}=\dfrac{2}{2}=1\\\\\text{y-value of vertex:}\ f(1) = (1)^2-2(1)-3\quad \longrightarrow \quad y = 1 - 2 - 3=-4\\\\\text{y-intercept:}\ f(0)= (0)^2-2(0)-3\ \longrightarrow \ y=0 - 0 - 3 = -3 \\

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<em>see attached</em> - the graphs intersect at two points:  (-2, 5) and (2, -3)


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