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3 years ago

Ill give brainliest hurry plssss

Mathematics

1 answer:

sattari [20]3 years ago

7 0

Answer:

Just solve the equation for g. You do this by moving all the g terms to one said and then getting the g term alone on that side.

a. 4.3g + 8 = 2.3g + 16

4.3g - 2.3g + 8 = 2.3g - 2.3g + 16 (Subtract 2.3g from both sides)

2g + 8 - 8 = 16 - 8 (Subtract 8 from both sides)

2g / 2 = 8 / 2 (Divide 2 from both sides)

g = 4

b. In order to check if your value is correct, simply substitute it in for g in the original equation

4.3(4) + 8 = 2.3(4) + 16

17.2 + 8 = 9.2 + 16

25.2 = 25.2

Since both sides are equal then our solution is correct. If the check didn't work, then we did our calculations wrong and need to redo it.

Step-by-step explanation:

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What is the sales tax on a jacket at 750 of the sales tax rate is 7%

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Sales tax is $52.50

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3 years ago

Given a standard deck of 52 cards, 3 cards are dealt without replacement. Using this situation, answer the questions below.<b

kherson [118]

Given that 3 cards are dealt without replacement in a standard deck of 52 cards.

Part A:

There are 4 queens in a standard deck of 52 card, thus the probability that the first card is a queen is given by 4 / 52 = 1 / 13.

Since, the first card is not replaced, thus there are 3 queens remaining and 51 ards remaining in total, thus the probability that the second card is a queen is given by 3 / 51 = 1 / 17

Similarly the probability that the third card is a queen is given by 2 / 50 = 1 / 25.

Therefore, the probability that all three cards are queens is given by

$\frac{1}{13} \times \frac{1}{17} \times \frac{1}{25} = \frac{1}{5525}$

Part B:

Yes the probability of drawing a queen of heart is independent of the probability of drawing a queen of diamonds because they are separate cards and drawing one of the cards does not in any way affect the chance of drawing the other card.

Part C:

Given that the first card is a queen, then there are 3 queens remaining out of 51 cards remaining, thus the number of cards that are not queen is 51 - 3 = 48 cards.

Therefore, if the first card is a queen, the probability that the second card will not be a queen is given by 48 / 51 = 16 / 17

Part D:

Given that the first two card are queens, then there are 2 queens remaining out of 50 cards remaining.

Therefore, if two of the three cards are queens ,the probability that you will be dealt three queens is given by 2 / 50 = 1 / 25 = 0.04

Part E:

Given that the first two card are queens, then there are 2 queens remaining out of 50 cards remaining, thus the number of cards that are not queen is 50 - 2 = 48 cards.

Therefore, if two of the three cards are queens ,the probability that the other card is not a queen is given by 48 / 50 = 24 / 25 = 0.96

8 0

3 years ago

How did you get 1845 when I got 1890

NemiM [27]

This question should be more specific

3 0

3 years ago

A pizza shop sells three sizes of pizza, and they track how often each size gets ordered along with how much they profit from ea

777dan777 [17]

Answer:

The mean and standard deviation of Y is $6.56 and $2.77 respectively.

Step-by-step explanation:

Consider the provided information.

Let Y represent their profit on a randomly selected pizza with this promotion.

The company is going to run a promotion where customers get $2 off any size pizza.

Therefore, $Y=\text{Profit}-\$2$

$Y=X-\$2$

So the mean will be reduced by 2.

$\mu_Y=\mu_X-\$2$

$\mu_Y =\$ 8.56 - \$2$

$\mu_Y =\$6.56$

If we add or subtract any constant number from a given distribution, then the mean is changed by the same number(i.e constant number) but the standard deviation will remain the same.

Therefore $\sigma_Y=\sigma_X=2.77$

Hence, the mean and standard deviation of Y is $6.56 and $2.77 respectively.

3 0

3 years ago