48
1st seat 6 possible for each 6 only 1 possible(spouse) for seat 2
3rd seat 4 possible for each 4 only 1 possible(spouse) for seat 4
5th seat 2 possible for each 2 only 1 possible(spouse) for seat 6
6 x 4 x 2 = 48
OR 3 couples possible arrangements 3 x 2 x1 = 6
each couple 2 possible 2 x 2 x 2 = 8
therefore 6 x 8 = 48
Answer:
Anything in the form x = pi+k*pi, for any integer k
These are not removable discontinuities.
============================================================
Explanation:
Recall that tan(x) = sin(x)/cos(x).
The discontinuities occur whenever cos(x) is equal to zero.
Solving cos(x) = 0 will yield the locations when we have discontinuities.
This all applies to tan(x), but we want to work with tan(x/2) instead.
Simply replace x with x/2 and solve for x like so
cos(x/2) = 0
x/2 = arccos(0)
x/2 = (pi/2) + 2pi*k or x/2 = (-pi/2) + 2pi*k
x = pi + 4pi*k or x = -pi + 4pi*k
Where k is any integer.
If we make a table of some example k values, then we'll find that we could get the following outputs:
- x = -3pi
- x = -pi
- x = pi
- x = 3pi
- x = 5pi
and so on. These are the odd multiples of pi.
So we can effectively condense those x equations into the single equation x = pi+k*pi
That equation is the same as x = (k+1)pi
The graph is below. It shows we have jump discontinuities. These are <u>not</u> removable discontinuities (since we're not removing a single point).
Answer:
The mean.
Step-by-step explanation:
I would use the mean as the measure of central tendency.
It is the best representation of the data as the variability isn't high; I'd only use the median if outliers are present because outliers don't affect it.
Because there are no outliers here, the mean is better.
Hopefully I helped :)