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Dennis_Churaev [7]
2 years ago
7

Review (a NBT 6.4 NF3e, MD sa, AG

Mathematics
2 answers:
Aleks [24]2 years ago
7 0
To find out each week, you would need to divide $1,472 by 4 weeks.
$1,472 ÷ 4 = 368
Papessa [141]2 years ago
6 0
The answer is 368 divide 1478 by 4 and you get 368 to check the answer you can multiply 368 by 4 and get 1472
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Please help!! will give brainliest and 20points!!! SUPER EASY PROBLEM
Fiesta28 [93]

Answer:

C. 184 ft²

Step-by-Step Explanation:

The formula for the surface area of a triangular prism is

SA = bh + 2ls + lb; where b = base, h = height, l = length, s = side

First, substitute the known value into the equation:

b = 6 ft

h = 4 ft

l = 10 ft

s = 5 ft

SA = (6)(4) + 2(10)(5) + (10)(6)

Then, all we have to do is simplify:

SA = 24 + 2(50) + 60

SA = 24 + 100 + 60

SA = 184 ft²

Hope this helps!

5 0
3 years ago
What is not a solution of -4 < x
Gnesinka [82]

Answer:

-5

Step-by-step explanation:

because it is less than -4 when it is suppose to be more than-4

8 0
3 years ago
Read 2 more answers
Rafael writes an expression to represent “a number, n, decreased by thirty-one.” Then he evaluates that expression if n=29. Whic
yulyashka [42]
This is a subtraction expression.o evaluate, substitute 29 for the variable in the expression.to<span>evaluate the expression, subtract 31 from 29.</span>
3 0
3 years ago
Read 2 more answers
If the least value of n is 3, which inequality best shows all the possible values of n?
andrezito [222]

Answer:

1) B. n ≥ 3

2)A. 5x – 9

Step-by-step explanation:

1)

If the least value of n is 3 then all the values of n must be greater or equal to 3

Thus the correct option is B :n ≥ 3

2)

Given:

Milo's age is 9 years less than 5 times Pearl's age

Pearl's age is x years

5 times Pearl's age= 5x

then milo's age= 5x-9

so the correct option is A. 5x – 9 !

4 0
3 years ago
How do you create and solve equations in one variable given a real–world situation?
WINSTONCH [101]

Step-by-step explanation:

1) first eliminate constant(number without variable) you eliminate constant by doing the inverse operation(if constant is being added, then subtract)(if constant is being subtracted, then add it)

ex: if   x+9=32

subtract 9 from both sides to get rid of it

x=23

2) if there is another constant but this constant is being multiplied/divided then do the opposite operation to remove it

you could multiply by 3 on both sides:

x+9=69

x=60

5 0
2 years ago
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