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anastassius [24]
3 years ago
6

A recipe calls for 2 2/4 cups of raisins , but julie only has a 1/4 cup measuring cup. how many 1/4 cups does julie need to meas

ure out 2 2/4 cups pf raisins ?
Mathematics
1 answer:
Veronika [31]3 years ago
5 0
She needs to put in 10 scoops 
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The time spent dancing (minutes) and the amount of calories burned can be modeled by the equation c = 5.5t. Which table of value
pishuonlain [190]
To build the table you just have to give values to t and then calculate the corresponding c a per the model.


If the model is c = 5.5 t this is the table

t          c
           5.5 t

0         5.5(0) = 0

1         5.5(1) = 5.5

2          5.5(2) = 11.0

3         5.5(3) = 16.5

4          5.5(4) = 22.0

5          5.5(5) = 27.5


The viables solutions are all where t is equal or greater than 0. You can even use decimal values for t. You cannot use negative values for t.
5 0
3 years ago
Read 2 more answers
Find the missing letter which is N.the length is 25 in and the perimeter is 86 in <br>​
Illusion [34]

Answer:

Step-by-step explanation:

length = 25 in

Perimeter = 86 in

2*(length + width) = 86

2*(25 + N) = 86

Divide both sides by 2

25 + N = 86/2

25 + N = 43

Subtract 25 from both sides

25 + N - 25 = 43 - 25

N = 18

7 0
3 years ago
If a and b are positive numbers, find the maximum value of f(x) = xa(7 â x)b on the interval 0 ⤠x ⤠7.
algol [13]
Given f(x)=x^a(7-x)^b on the interval 0 ≤ x ≤ 7, for maximum value, f'(x) = 0.

f'(x)=0 \\  \\ \Rightarrow -bx^{a}(7-x)^{b-1}+ax^{a-1}(7-x)^b=0 \\  \\ \Rightarrow ax^{a-1}(7-x)^b=bx^{a}(7-x)^{b-1} \\  \\ \Rightarrow a(7-x)=bx \\  \\ \Rightarrow (a+b)x=7a \\  \\ \Rightarrow x= \frac{7a}{a+b}
8 0
3 years ago
Can you plz help with this?
Oduvanchick [21]
Plug in the side length (5) for “s” to get SA=6(5)^2.
Solving this, we get 150 square meters
4 0
2 years ago
Read 2 more answers
Use the tangent identity to
Lunna [17]

Answer:

tan(x)=\frac{44\sqrt{89}}{89}

Step-by-step explanation:

tan is defined as: tan(x)=\frac{opposite}{adjacent}

sin is defined as: sin(x)=\frac{opposite}{hypotenuse}

cos is defined as: cos(x)=\frac{adjacent}{hypotenuse}

We can also define tan as: tan(x)=\frac{sin(x)}{cos(x)}

because plugging in the definitions of sin and cos in we get: tan(x)=\frac{(\frac{opposite}{hypotenuse})}{(\frac{adjacent}{hypotenuse})}\\\\tan(x)=\frac{opposite}{hypotenuse}*\frac{hypotenuse}{adjacent}\\\\tan(x)=\frac{opposite}{adjacent}

which you'll notice is the original definition of tan(x)

So using this definition of tan(x) we can use the givens sin(x) and cos(x) to find tan(x)

sin(x)=\frac{44}{45}\\\\cos(x)=\frac{\sqrt{89}}{45}\\\\tan(x)=\frac{sin(x)}{cos(x)}

plugging in sin(x) and cos(x) we get:

tan(x)=\frac{\frac{44}{45}}{\frac{\sqrt{89}}{45}}\\\\tan(x)=\frac{44}{45}*\frac{45}{\sqrt{89}}\\\\tan(x)=\frac{44}{\sqrt{89}}

We usually don't like square roots in the denominator, and from here we want to rationalize the denominator which we do by removing the square root from the denominator.

We can do this by multiplying the fraction by: \frac{\sqrt{89}}{\sqrt{89}} which doesn't change the value of the fraction since it simplifies to 1, but it gets rid of the square root in the denominator

tan(x)=\frac{44}{\sqrt{89}}*\frac{\sqrt{89}}{\sqrt{89}}\\\\tan(x)=\frac{44\sqrt{89}}{89}

5 0
10 months ago
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