In this case just do it left to right, as multiplication comes before addition/subtraction. So 7x3x2+5-3=21x2+5-3=42+5-3=47-3=44=k.
Answer:
2
Step-by-step explanation:
139 + 30d = 13 + 51d
139 - 13 = 51d - 30d
126 = 21d
126/21 = d
6 = d
now lets check..
139 + 30d = 139 + 30(6) = 319
13 + 51d = 13 + 51(6) = 319
so on day 6, they will both cost $ 319
Answer:
Option C) Critical value is based on the significance level and determines the boundary for the rejection region
Step-by-step explanation:
Critical Value:
- In hypothesis testing, a critical value is a point that is compared to the test statistic
- It is used to determine whether to reject the null hypothesis or accept the null hypothesis.
- If the absolute value of your test statistic is greater than the critical value,we fail to accept the null hypothesis and reject it.
- Critical value is affected by the significance level of the testing.
- It is the value that a test statistic must exceed in order for the the null hypothesis to be rejected.
Thus, option C) is the correct interpretation of critical values.
Option C) Critical value is based on the significance level and determines the boundary for the rejection region
Since the height of an equilateral triangle in terms of its side s is s√3/2, the height of the triangle is 6√3/2 = 3√3 and so the area is (1/2)(6)(3√3) = 9√3.
<span>If we draw a horizontal line a height of h from the base of the triangle, the region is split into two regions: the lower region consisting of a trapezoid of height h and the upper region consisting of a triangle of height 3√3 - h. </span>
<span>Since the upper triangle and the triangle itself are similar triangles, the base and height are proportional. If we let x denote the base of the length of the upper triangle, we have: </span>
<span>(S. of small triangle)/(S. of big triangle) = (Ht. of small triangle)/(Ht. of big triangle) </span>
<span>==> x/6 = (3√3 - h)/(3√3) </span>
<span>==> x = (6√3 - 2h)/√3 </span>
<span>Thus, the area of the upper triangle is: </span>
<span>A = (1/2)[(6√3 - 2h)/√3](3√3 - h) = [(6√3 - 2h)(3√3 - h)]/(2√3). </span>
<span>(Made a dumb mistake about the height here for some reason) </span>
<span>Since we require that the area of this triangle is to be half of the total area (9√3/2), we need to solve: </span>
<span>[(6√3 - 2h)(3√3 - h)]/(2√3) = 9√3/2 </span>
<span>==> (6√3 - 2h)(3√3 - h) = 27 </span>
<span>==> 54 - 6h√3 - 6h√3 + 2h^2 = 27 </span>
<span>==> 2h^2 - 12h√3 + 27 = 0. </span>
<span>Solving with the Quadratic Formula gives: </span>
<span>h = (6√3 + 3√6)/2 ≈ 8.87 units and h = (6√3 - 3√6)/2 ≈ 1.52 units. </span>
<span>Since h = (6√3 + 3√6)/2 would place the line outside of the triangle, we pick h = (6√3 - 3√6)/2. </span>
<span>Therefore, the line should be ==> (6√3 - 3√6)/2 units from the base. </span>
<span>I hope this helps! ^^ Brainliest Please?</span><span>
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