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4 years ago

• What is the solution to 5x+ 20 = 7(x+2)?

Mathematics

1 answer:

o-na [289]4 years ago

6 0

For this case we must find the solution of the following equation:

$5x + 20 = 7 (x + 2)$

Applying distributive property on the right side of the equation we have:

$5x + 20 = 7x + 14$

Subtracting 7x from both sides of the equation:

$5x-7x + 20 = 14\\-2x + 20 = 14$

Subtracting 20 from both sides of the equation:

$-2x = 14-20$

Different signs are subtracted and the major sign is placed.

$-2x = -6$

Dividing between -2 on both sides of the equation:

$x = \frac {-6} {- 2}\\x = 3$

Thus, the solution of the equation is $x = 3$

Answer:

$x = 3$

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How do I find the sides of a rhombus?

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Answer:

count them

Step-by-step explanation:

Start with 1 and go to 2 and keep going till u get back to the first one u counted.

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3 years ago

Consider the population of four juvenile condors. Their weights in pounds are : 4, 5, 7, 12 (a) Let x be the weight of a juvenil

creativ13 [48]

Answer:

a) 4, 5, 7, 12

b) 7

c) 4.5, 6.5, 8, 6, 8.5, 9.5

d) 7.167

Step-by-step explanation:

We are given the following in the question:

4, 5, 7, 12

a) unique values for x

4, 5, 7, 12

b) mean of the population

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$\mu =\displaystyle\frac{28}{4} = 7$

c) sampling distribution for samples of size 2

Sample size, n = 2

Possible samples of size 2 are (4,5),(4,7),(4,12),(5,7),(5,12),(7,12)

Sample means are:

$\bar{x_1} = \dfrac{4+5}{2} = 4.5\\\\\bar{x_2} = \dfrac{4+7}{2} = 6.5\\\\\bar{x_3} = \dfrac{4+12}{2} = 8\\\\\bar{x_4} = \dfrac{5+7}{2} = 6\\\\\bar{x_5} = \dfrac{5+12}{2} = 8.5\\\\\bar{x_6} = \dfrac{7+12}{2} = 9.5$

Thus, the list is 4.5, 6.5, 8, 6, 8.5, 9.5

d) mean of the sampling distribution

$\bar{x} = \dfrac{4.5 + 6.5 + 8+ 6 + 8.5+ 9.5}{6} = \dfrac{43}{6} = 7.167$

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3 years ago

Find the value of the variable: 3(y + 8) =36

max2010maxim [7]

Answer:

Step-by-step explanation: Step 1: Simplify both sides of the equation.

3(y+8)=36

(3)(y)+(3)(8)=36(Distribute)

3y+24=36

Step 2: Subtract 24 from both sides.

3y+24−24=36−24

3y=12

Step 3: Divide both sides by 3.

3y/3=12/3

y=4

3 0

3 years ago

Read 2 more answers

A certain forest covers an area of

iVinArrow [24]

Answer:

2598 square kilometers

Step-by-step explanation:

Hello

Step 1

year one

using a rule of three is possible to find how much is 8.75 od 4500 km2

Let

4500 km2 ⇒ 100$

x?km2 ⇒8.75

do the relation and isolate x

$4500:100\\x:8.75\\\frac{4500}{100}=\frac{x}{8.75}\\x=\frac{4500*8.75}{100} \\x=393.75\\$

at the end of the year one, the area will be

4500-393.75=4106.25

this will be the initial area for the year 2.

Step 2

repite the step 1 with area initial =4106.25 km2

4106.25 km2 ⇒ 100$

x?km2 ⇒8.75

do the relation and isolate x

$4106.25:100\\x:8.75\\\frac{4106.25}{100}=\frac{x}{8.75}\\x=\frac{4106.25*8.75}{100} \\x=359.29\\$

at the end of the year 2, the area will be

4106-359.29=3746.70

this will be the initial area for the year 3.

Step 3

repite the step 1 with area initial =4106.25 km2

3746.70 km2 ⇒ 100$

x?km2 ⇒8.75

do the relation and isolate x

$3746.70:100\\x:8.75\\\frac{3746.70}{100}=\frac{x}{8.75}\\x=\frac{3746.7*8.75}{100} \\x=327.83\\$

at the end of the year 3, the area will be

3746.70-327.83=3419.09

this will be the initial area for the year 4.

Step 4

year four

repite the step 1 with area initial =3419.09 km2

3419.09 km2 ⇒ 100$

x?km2 ⇒8.75

do the relation and isolate x

$3419.09:100\\x:8.75\\\frac{3419.09}{100}=\frac{x}{8.75}\\x=\frac{3419.09*8.75}{100} \\x=299.17\\$

at the end of the year 4, the area will be

3419.09-299.173=3119.82

this will be the initial area for the year 5.

Step 5

year five

repite the step 1 with area initial =3119.82 km2

3119.82 km2 ⇒ 100$

x?km2 ⇒8.75

do the relation and isolate x

$3119.82:100\\x:8.75\\\frac{3119.82}{100}=\frac{x}{8.75}\\x=\frac{3119.82*8.75}{100} \\x=272.99\\$

at the end of the year 5, the area will be

3119.82-272.99=2846.92

this will be the initial area for the year 6.

Step 6

year six

repite the step 1 with area initial =2846.92km2

2846.92 km2 ⇒ 100$

x?km2 ⇒8.75

do the relation and isolate x

$2846.92:100\\x:8.75\\\frac{2846.92}{100}=\frac{x}{8.75}\\x=\frac{2846.92*8.75}{100} \\x=249.10\\$

at the end of the year six, the area will be

2846.92-249.10=2597.82 square kilometers

Have a great day.

8 0

3 years ago

Kara has a piece of ribbon that is 24 inches long. She know that this piece of rib ion is 2 feet long.

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Every foot is 12 inches

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4 years ago